Answer:
inelastic, since the girl moves in the same direction as the thrown ball
Explanation:
yess this ok
UwU
The surface of the paper is phosphorescent. When light shines on it, some of the energy is absorbed and re-emitted slowly over t
1 answer:
Answer:
No
Explanation:
Recall that the hierarchy of wavelength color from minimum wavelength to maximum wavelength is:
and
As a result, blue light has a higher energy level than green and red light.
As a result, the surface glows due to the blue LED. The green LED, on the other hand, would not allow the surface to glow as much as the red LED, which has a lower energy level when compared to the green light. As a result, the red LED would not allow the surface to glow as well.
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Answer:
Explanation:
magnetic flux is the count of magnetic field lines passing through a given loop or area
As we know that magnetic flux is given by the formula
here we also know that magnetic field B and plane of the coil is perpendicular in initial position
So the area vector is always perpendicular to the plane of the coil
so the angle between magnetic field and area vector is parallel to each other and this angle would be zero
so magnetic flux of the coil initially we have
Answer:
Explanation:
I got everything but i. Don't know why but it's eluding me. So let's do everything but that.
a. PE = mgh so
PE = (2.5)(98)(14) and
PE = 340 J
b. so
and
KE = 250 J
c. TE = KE + PE so
TE = 340 + 250 and
TE = 590 J
d. PE at 8.7 m:
PE = (2.5)(9.8)(8.7) and
PE = 210 J
e. The KE at the same height:
TE = KE + PE and
590 = KE + 210 so
KE = 380 J
f. The velocity at that height:
and
so
v = 17 m/s
g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:
590 = KE + PE and
PE = (2.5)(9.8)(11.6) so
PE = 280 then
590 = KE + 280 so
KE = 310 then
and
so
v = 16 m/s
h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:
and
26 = 0 + 9.8t and
26 = 9.8t so the time at 26 m/s is
t = 2.7 seconds. Now we use that in the equation for displacement:
Δx = and filling in the time the object was at 26 m/s:
Δx = 0t + so
Δx = 36 m
i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.