Answer:
or
Step-by-step explanation:
yz-plane has the equation 
where 
is a real constant. The normal vector of this plane (vector perpendicular to the plane) is
If the line is perpendicular to this plane, then it is parallel to the normal vector, so the equation of this line is
where 
are coordinates of the point the line is passing through.
In your case, the line is passing through the point (0,0,8), so the canonical equation of the line is
Write a vector parametrization for this line
quick question is the 1 2 3 4 and 5 the answer options?
4.25(15)+4.25(1.5)(7)+0.21(1345)=
63.75+44.625+282.45=$390.825
=$390.83
Answer:
sdf67566655 so x is 129
Step-by-step explanation:
ytr654564676
Answer:
idk
Step-by-step explanation:
im really stupid I need the points to ask my own question
