Answer:
The minimum number of grams of acetic acid that we would need to fully react with your NaHCO3, is 0.263 grams.
Explanation:
Step 1: Data given
Mass weigh boat = 1.5624 grams
Mass of boat + NaHCO3 = 1.92...
<u>Step 2:</u> Calculate ranges
The minimum possible mass of boat + NaHCO3 = 1.9200g
Minimum mass of NaHCO3 = 1.9200g - 1.5624g = 0.3576g
The maximum possible mass of boat + NaHCO3 = 1.9299g
Maximum mass of NaHCO3 = 1.9299g - 1.5624g = 0.3675g
What is the minimum mass of acetic acid that must be used to react with all the NaHCO3 possible in the boat:
This means what mass of CH3COOH reacts with 0.3675g NaHCO3
NaHCO3 + CH3COOH → CH3COONa + CO2 + H2O
1 mole of NaHCO3 consumed, needs 1 mole CH3COOH to produce 1 mole of CH3COONa, 1 mole CO2 and 1 mole H2O
<u>Step 3: </u>Calculate moles NaHCO3
Moles NaHCO3 = mass NaHCO3 / Molar mass NaHCO3
moles NaHCO3 = 0.3675 grams / 84g/mol
moles NaHCO3 = 0.004375 moles
Since 1 mole of NaHCO3 consumed, needs 1 mole CH3COOH
For 0.004375 moles NaHCO3, we need 0.004375 moles CH3COOH
<u>Step 4:</u> Calculate mass of CH3COOH
mass of CH3COOH = moles CH3COOH * Molar mass CH3COOH
mass of CH3COOH = 0.004375 moles * 60.05 g/mol
mass CH3COOH = 0.2627 grams ≈ 0.263 grams
The minimum number of grams of acetic acid that we would need to fully react with your NaHCO3, is 0.263 grams.
