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Lostsunrise [7]
2 years ago
11

Victoria turned in a rough draft of a research paper. Her teacher commented that the organization of the paper needs work.

Computers and Technology
2 answers:
kykrilka [37]2 years ago
8 0

D would be correct

EDGE 2021

Katarina [22]2 years ago
4 0

Answer:

D

Explanation:

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What feature did we use to quickly apply the formatting shown in this image?
hammer [34]

Answer:

Conditional formatting.

Explanation:

Conditional Formatting is the method that main objective to enabling the users for setting the formatting to the  cell or the cell range as well as it adjust the layout based that are based on the cell value or the formula value.

  • The Conditional formatting making the cell value as bold as in the given question we see that the cell value is bold  when the given condition is true.
  • The objective of pivot table is to summarizing the data it do not provide the formatting that's why this option is incorrect .
  • The objective of what if analysis is altering the absolute value of worksheet also it see how some modifications will influence the result of the worksheet formulae in the spreadsheet it do not provide the formatting that's why this option is incorrect .
  • Data scenario formatting do not provide the formatting that's why this option is incorrect .

3 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
Two negative reviews and no positive reviews is enough to consider the website to have a negative reputation.
Bas_tet [7]

Two negative reviews and no positive reviews is enough to consider the website to have a negative reputation: False.

<h3>What is reputation?</h3>

In Computer technology, reputation can be defined as a metric which is used to determine the quality of a particular website, especially based on the opinions and ratings by its end users.

In this context, we can infer that two negative reviews and no positive reviews isn't an enough metric to consider a website as having a negative reputation.

Read more on negative reputation here: brainly.com/question/2343924

#SPJ1

4 0
2 years ago
Create a script that prompts for the user to input a directory and then prints out the number of sub-directories in the given di
laila [671]

Answer:

Below is the required code:

Explanation:

Python Code

import os

import bin

dir = input("Please specify the location to the directory")

list = os.walk(dir)

a = length(list[1])

b = length(list[2])

print "Files: %n , Sub-dirs : %n" % (b,a)

decision = _(" Do you want to continue? (y/n) "))

if(decision):

cls

else :

exit()

5 0
2 years ago
What can geographers map with remotely sensed data?
horsena [70]
Geographers can map for example the topography of the earth's surface using aerial photographs taken from a plane flying on regular flight paths at known altitudes. A topographic map with regular contour intervals and also showing infrastructure like roads and buildings can be created from this. Also, the LIDAR system can show features not observable on the ground by 'seeing' into the subsurface and detecting buried escarpments, trenches etc. 
7 0
3 years ago
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