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lianna [129]
3 years ago
11

The categories of a categorical variable are given along with the observed counts from a sample. The expected counts from a null

hypothesis are given in parentheses. Compute the x-test statistic, and use the x-distribution to find the p-value of the test. Category Observed (Expected) A 25 (20) B 35(40) C 50(60) D 90(80) Round your answer for the chi-square statistic to two decimal places, and your answer for the p-value to four decimal places. chi-square statistic = p-value = i
Mathematics
1 answer:
noname [10]3 years ago
5 0

Answer:

χ² = 4.80

Pvalue = 0.1874

Step-by-step explanation:

Given :

Category Observed (Expected)

A 25 (20)

B 35(40)

C 50(60)

D 90(80)

The Chisquare statistic (χ²) is given by :

χ² = Σ(observed - Expected)² / Expected

χ² = (25-20)²/20 + (35-40)/40 + (50-60)²/60 + (90-80)²/80

χ² = 1.25 + 0.625 + 1.67 + 1.25

χ² = 4.795

χ² = 4.80 (2 decimal places)

Using the Chisquare Pvalue calculator :

df = n - 1 = 4 - 1 = 3

Pvalue = 0.1874

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Lilit [14]

Answer:A

Step-by-step explanation: The first few square numbers are:

1

,

4

,

9

,

16

,

25

,

36

,

49

,

√

1

=

1

√

4

=

2

√

9

=

3

√

16

=

4

√

25

=

5

√

36

=

6

w

w

w

w

w

w

←

√

40

lies here

√

49

=

7

Therefore

√

40

is between

6

and

7

8 0
3 years ago
Read 2 more answers
What makes this statment true 9^-2=?<br> a)81<br> b)18<br> c)1/81<br> d)-1/81
inna [77]

Answer:

The answer is C

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Expand and simplify (n-2)(3n+7) + 2n(2n+3)
KonstantinChe [14]
3n^2+7n-6n-14+4n^2+6n= 7n^2+7n-14

Hope that helps and best of wishes!
6 0
3 years ago
Having a problem solving for h in this algebra problem. A=1/2h(B+b); A=35, B=6, b=1 <br> So h=?
ivann1987 [24]
35 = 1/2h (6+1)
35 = 1/2 h + 7
28 = 1/2h
14 = 1h
14 = h
8 0
3 years ago
Read 2 more answers
G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =
laiz [17]

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of (h\circ g)(-6).

Solution:

We have,

g(b)=5b-9

h(b)=(b-1)^2

We know that,

(h\circ g)(b)=h(g(b))

(h\circ g)(b)=h(5b-9)

(h\circ g)(b)=[(5b-9)-1]^2

(h\circ g)(b)=[5b-10]^2

Putting b=-6, we get

(h\circ g)(-6)=[5(-6)-10]^2

(h\circ g)(-6)=[-39-10]^2

(h\circ g)(-6)=[-49]^2

(h\circ g)(-6)=2401

Therefore, the value of (h\circ g)(-6) is 2401.

7 0
3 years ago
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