hmax = 5740.48 m. The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.
This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.
V₀ = 420m/s and θ₀ = 53.0°
So, when the cannonball is fired it has horizontal and vertical components:
V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s
V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s
When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:
Vy = V₀y - g tₐ = 0
tₐ = V₀y/g
tₐ = (335.43m/s)/(9.8m/s²) = 34.23s
Then, the maximum height is reached in the instant tₐ = 34.23s:
h = V₀y tₐ - 1/2g tₐ²
hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²
hmax = 11481.77m - 5741.29m
hmax = 5740.48m
It is made like the reflect in presence of magnetism. It gets deflected on earth towards north also because of a huge magnetism of earth.
Lets use Dimensional analysis.
<h3>LHS:-</h3>
<h3>RHS</h3>
LHS=RHS
Hence verified
Answer:
The intralveolar pressure is 1 mmHg
Explanation:
The transpulmonary pressure is the difference between the alveolar pressure and the intrapleural pressure. It is this gradient between pressures that allows the air to flow during human ventilation.
Writing this into an equation it means that, Ptp = Palv - Pip, so from there we have Palv = Ptp + Pip, or Palv = 5 mmHg - 4 mmHg = 1 mmHg.
Answer:
a vacuum formed above the column of mercury in a mercury barometer.