Answer:
is it bad if i keep thinking about p ussy
Explanation:
A persons or animals nature, especially as it permanently affects their behavior
Answer:
Approximately
(assuming that the melting point of ice is
.)
Explanation:
Convert the unit of mass to kilograms, so as to match the unit of the specific heat capacity of ice and of water.
![\begin{aligned}m&= 100\; \rm g \times \frac{1\; \rm kg}{1000\; \rm g} \\ &= 0.100\; \rm kg\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dm%26%3D%20100%5C%3B%20%5Crm%20g%20%5Ctimes%20%5Cfrac%7B1%5C%3B%20%5Crm%20kg%7D%7B1000%5C%3B%20%5Crm%20g%7D%20%5C%5C%20%26%3D%200.100%5C%3B%20%5Crm%20kg%5Cend%7Baligned%7D)
The energy required comes in three parts:
- Energy required to raise the temperature of that
of ice from
to
(the melting point of ice.) - Energy required to turn
of ice into water while temperature stayed constant. - Energy required to raise the temperature of that newly-formed
of water from
to
.
The following equation gives the amount of energy
required to raise the temperature of a sample of mass
and specific heat capacity
by
:
,
where
is the specific heat capacity of the material,
is the mass of the sample, and
is the change in the temperature of this sample.
For the first part of energy input,
whereas
. Calculate the change in the temperature:
.
Calculate the energy required to achieve that temperature change:
.
Similarly, for the third part of energy input,
whereas
. Calculate the change in the temperature:
.
Calculate the energy required to achieve that temperature change:
.
The second part of energy input requires a different equation. The energy
required to melt a sample of mass
and latent heat of fusion
is:
.
Apply this equation to find the size of the second part of energy input:
.
Find the sum of these three parts of energy:
.
Answer:
current going into a junction in a circuit is EQUAL TO the current comming out of the junction.
Explanation:
Krichhoff's Current Law
Kirchhoff's current law (1st Law) states that current flowing into a node (or a junction) must be equal to current flowing out of it.
Answer: The net force acting on the car 1,299.3 N.
Explanation:
Mass of the car = 710 kg
Initial velocity of the car of the ,u= 37 km/h= 10.27 m/s ![(1km\h=\frac{5}{18} m/s)](https://tex.z-dn.net/?f=%281km%5Ch%3D%5Cfrac%7B5%7D%7B18%7D%20m%2Fs%29)
Final velocity of the car,v = 120 km/h = 33.33 m/s
time taken b y car = 12.6 sec
v-u=at
![33.33m/s-10.27m/s=23.06 m/s=a(12.6 sec)](https://tex.z-dn.net/?f=33.33m%2Fs-10.27m%2Fs%3D23.06%20m%2Fs%3Da%2812.6%20sec%29)
![a = 1.83 m/s^2](https://tex.z-dn.net/?f=a%20%3D%201.83%20m%2Fs%5E2)
![Force=mass\times acceleration](https://tex.z-dn.net/?f=Force%3Dmass%5Ctimes%20acceleration)
![Force=710 kg\times 1.83 m/s^2](https://tex.z-dn.net/?f=Force%3D710%20kg%5Ctimes%201.83%20m%2Fs%5E2)
![Force=1,299.3 N](https://tex.z-dn.net/?f=Force%3D1%2C299.3%20N)
The net force acting on the car 1,299.3 N.