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A student is concerned about background radiation that she is exposed to. She claims that nuclear power plants have caused backg

denis-greek [22]

Based on the given statement or reasoning above made by a student, what makes her reasoning incorrect is the part where she mentioned that "if they had not been built, she would not be exposed to radioactivity." This is definitely false. What makes this incorrect is that background radiation is a kind of radiation that is emitted by the sun, stars, and other bodies outside the universe and therefore, no one can escape from this. Hope this helps.

5 0

2 years ago

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Students should only talk to friends when struggling to make a decision rather than a parent, teacher, or school counselor. Plea

mojhsa [17]

False, some adults will know more than your friends as they are already grown up and may have experienced the problem already

3 0

3 years ago

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A 4.28 m deep well acts as a closed pipe. When wind blows across the top, what is the third harmonic (f3) that it creates?

Ksenya-84 [330]

The third harmonic frequency from the wave speed is 60.1 Hz.

<h3>What is wavelength?</h3>

Wavelength is the distance between identical points in the adjacent cycles of a waveform signal propagated in space or along a wire.

Let's first find the wavelength of the wave.

The length wavelength relationship

$\lambda = \frac{4}{3} L = \frac{4}{3} . 4.28m = 5.706m$

Now , we will find the third harmonic frequency from the wave speed formula:

$v = f\lambda \\\\f = \frac{v}{\lambda} \\\\f = \frac{343\frac{m}{8} }{5.706m} \\\\f = 60.1 Hz$

Therefore , the third harmonic (f3) is 60.1 Hz

Learn more about harmonic frequency:

brainly.com/question/12320829

#SPJ1

4 0

1 year ago

What is the gamma factor for an object moving at 0.5c?

Anettt [7]

Answer:1.15

Explanation:

4 0

2 years ago

A flat loop of wire consisting of a single turn of cross-sectional area 7.00 cm2 is perpendicular to a magnetic field that incre

likoan [24]

To solve this problem we must first find the potential on the body which is given as a product between the number of turns, the area and the variation of the magnetic field as a function of time. Once the potential is found, we will apply Ohm's Law with which we can find the induced current on the body. Our values are,

$A = 7.00*10^{-4} m^2$