2 years ago

What is a equation when the slope is 6 and the y intercept -8

Mathematics

1 answer:

attashe74 [19]2 years ago

8 0

Answer:

y=6x-8 is the answer

Step-by-step explanation:

the formula is y=mx+b. m is the slope and b is the y intercept.

You might be interested in

Someones answer q3 ill mark as brainliest pleaseee

il63 [147K]

The length of the rectangle is x and the height is x-2

To find the area of a rectangle you multiply length times width

l(w) = 146

x(x-2) = 146

x^2 - 2x = 146

5 0

2 years ago

What is the slope of the line

lidiya [134]

Answer:

c is the correct answer

Step-by-step explanation:

because i worked it out

8 0

2 years ago

Read 2 more answers

arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)

cupoosta [38]

We have to rationalize the denominator:
$\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\ \frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{ \sqrt{x+y-2}+ \sqrt{x+y+2} }= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-(x+y+2)}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-x-y-2}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2} }{-4}= \\ \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{2}$