Simple pythagorus theorem with the equation a^2=b^2+c^2
To find AC, (2^2)+(3^2)=4+9=13
AC=the square root of 13
Answer:
4(p−1)(p−3)
Step-by-step explanation:
Factor 4p2−16p+12
4p2−16p+12
=4(p−1)(p−3)
Answer:
One
Step-by-step explanation:
Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)
To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.
Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.
Answer:
4 eggs are left.
Step-by-step explanation:
It is actually a tricky question and the trick is that the person, who initially have 6 eggs, has broken two eggs out of them.
Those two broken eggs were then fried and later he ate those.
It is a single incident but in question it appears that 3 different incidents took place in which the person have used all 6.
So actually, he only ate 2 eggs out of 6.
<span>Difference of squares method is a method that is used to evaluate the difference between two perfect squares.
For example, given an algebraic expression in the form:
can be factored as follows:
From the given expressions, the only expression containing two perfect squares with the minus sign in the middle is the expression in option A.
i.e.
which can be factored as follows:
.</span>
