Answer:
The dimensions of the frame are 15 in x 13 in
Step-by-step explanation:
Let
x ----> the length of the picture
y ----> the width of the picture
we know that
-----> equation A
The area of the picture, including the frame is


so
----> equation B
substitute equation A in equation B

solve for y

solve the quadratic equation by graphing
The solution is y=7 in
see the attached figure
<em>Find the value of x</em>

Find the dimensions of the frame


therefore
The dimensions of the frame are 15 in x 13 in
Step-by-step explanation:
by having two equations that have the same point, you can set the two equations equal to each other
y = 12x + 3, y = x + 1
12x + 3 = x + 1
11x = -2
x = -2/11
when you find the the x value, plug it back into either one of the equations
y = x + 1
y = (-2/11) + 1
y = 11/11 - 2/11
y = 9/11
the point (solution):
(-2/11, 9/11)
-- Both pairs of sides of a rectangle are parallel.
Only one pair of sides of a trapezoid are.
-- A rectangle is a parallelogram.
A trapezoid isn't.
-- The opposite sides of a rectangle are equal.
The opposite sides of a trapezoid aren't.
-- All of the angles of a rectangle are right angles.
The angles of a trapezoid aren't.
-- The area of a rectangle is the product of (length) times (width).
The area of a trapezoid is (height) times (the average of the two bases).
Every yard has 36 inches, so 7 yards is 252 inches