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3 years ago

I need help 8th grade math

Mathematics

2 answers:

snow_lady [41]3 years ago

7 0

The answer is c i believe

kodGreya [7K]3 years ago

6 0

I believe the answer is C

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Equation for 14+ W= 26

OLEGan [10]

Answer: w = 12

Step-by-step explanation: In this problem, we want to get w by itself on one side of the equation. Since we have 14 + W, in order to get w by itself, we must subtract 14 from the left side of the equation.

If we subtract 14 from the left side of the equation, we must also subtract 14 from the right side of the equation. So on the left, +14 and -14 cancel each other and on the right, 26 - 14 simplifies to 12 so w = 12.

To check our answer, we substitute a 12 back in for w in the original equation and we have 14 + (12) = 26 or 26 = 26 which is a true statement so the answer checks.

6 0

3 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago

Max is buying a home worth $250,000. He will pay 3 percent in closing costs and 12 percent for a down payment. Calculate how muc

Svet_ta [14]

Hey there, Lets solve this together,

We all know that you will start off with 250,000 and multiply that by 3%, which is the same thing as .03 in decimal form.

= 7500

You do the same thing again.

12%,= 30,000 for the down payment.

6 0

3 years ago

Special segments in circles

pochemuha

If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.
I'm assuming that number up top is an 8. It's kind of blurry.

Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
$24 = 10x - x^{2}$
$x^{2} - 10x + 24 = 0$
(x - 6)(x - 4) = 0
x - 6 = 0 .... x - 4 = 0
x = 6 .... x = 4

4 or 6

4 0

3 years ago

F x = 3, then what is the value of y? A) 0 B) 3 C) 4 D) 9

lana66690 [7]

The answer is: [B]: " 3 " .
__________________________________________
If f(x) = 3 ; then "y = 3" .
__________________________________________
(assuming this is the only information we are given).
__________________________________________

7 0

3 years ago