Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
Answer: $5 for each eraser
Step-by-step explanation:
$5 in magazines ( 1 magazine )
? in erasers ( 4 erasers total )
$25 in total
step 1. 25-5= 20
step 2. 20/4= 5
step 3. $5 = each eraser (some expensive erasers)
Answer:
when you divide a negative number by a negative number the quotient is always positive.when you divide two negative number then the quotient is always positive
Step-by-step explanation:
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I guess that is the answer.
Hope this helps !
Photon
Answer:
(2y - 5) (3y^2 - 4)
Step-by-step explanation:
Group and factor by using the Greatest Common Factor (GCF).
6y^3 - 15y^2 - 8y + 20
Simply multiply the terms inside the first pair of parenthesis, by the terms in the second pair of parenthesis.
2y x 3y^2 = 6y^3
2y x (-4) = 8y
-5 x 3y^2 = 15y^2
-5 x (-4) = 20
6y^3 - 8y -15y^2 + 20
Now, simply simplify the problem!
(2y - 5) (3y^2 - 4)
