36 different value meal packages are possible
Step-by-step explanation:
To answer this question, multiply all given numbers together.
4*3*3
12*3
36
If x is squared, that will be biggest by the end because it gets bigger the quickest. x^2 + 4 is always 4 greater than x^2, no matter what the value of x is.
5x+3 is always 3 greater than 5x also.
Besides that, you can rank them based on their slopes (5x < 7x < 8x, etc.)
So,
5x
5x + 3
7x
8x + 3
x^2
x^2 + 4
You can also just say “eventually” means that they’re asking to find the values of each when x is really big. so just choose x=100, and plug that into each one.
So, to check that order:
5(100) = 500
5(100) + 3 = 503
7(100) = 700
8(100) + 3 = 803
(100)^2 = 10,000
(100)^2 + 4 = 10,004
Those are in ascending order, so that must be the right order!
Answer:
4 plus the difference of 27 and 10
Step-by-step explanation:
Let
denote the <em>k</em>th term of the sequence. Then
![a_k=a_1+d(k-1)](https://tex.z-dn.net/?f=a_k%3Da_1%2Bd%28k-1%29)
where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.
The sum of the first <em>n</em> terms is
![S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n](https://tex.z-dn.net/?f=S_n%3D%5Cdisplaystyle%5Csum_%7Bk%3D1%7D%5Ena_k%3Da_1%2Ba_2%2B%5Ccdots%2Ba_%7Bn-1%7D%2Ba_n)
From the formula for
, we get
![S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)](https://tex.z-dn.net/?f=S_n%3D%5Cdisplaystyle%5Csum_%7Bk%3D1%7D%5En%28a_1%2Bd%28k-1%29%29%3Da_1%5Csum_%7Bk%3D1%7D%5En1%2Bd%5Csum_%7Bk%3D1%7D%5En%28k-1%29)
![S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k](https://tex.z-dn.net/?f=S_n%3D%5Cdisplaystyle%20na_1%2Bd%5Csum_%7Bk%3D0%7D%5E%7Bn-1%7Dk)
![S_n=na_1+\dfrac{d(n-1)n}2](https://tex.z-dn.net/?f=S_n%3Dna_1%2B%5Cdfrac%7Bd%28n-1%29n%7D2)
![S_n=\dfrac n2(2a_1-d+dn)](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%20n2%282a_1-d%2Bdn%29)
So we have
, and
so that
.
Then the <em>n</em>th term in the sequence is
![a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}](https://tex.z-dn.net/?f=a_n%3D%5Cdfrac%7B11%7D2-5%28n-1%29%3D%5Cboxed%7B%5Cdfrac%7B21-10n%7D2%7D)
Answer:
a) Vertex is at (-3, -1)
b) y-intercept is at (0,8)
c) x intercept is at (-4,0) and (-2,0)
d) x=-3
Step-by-step explanation:
We know the vertex is the lowest or highest part of a parabola meaning all the points are reflected across. It is the only y value without a matching pair
E.x. -1 and 1, -3 and 3
The only point without a corresponding y value is (-3,-1) therefore the vertex is at (-3,-1)
The y-intercept is where the parabola meets the y axis or the x value is equal to 0, we just have to find when x = 0 to find the y intercept
y intercept: (0,8)
For the x intercept's it is just the reverse, you need to find where the parabola crosses the x axis or when y = 0
x intercept 1:(-4,0)
x intercept 2: (-2,0)
The axis of symmetry is also the x coordinate of the vertex which is 3 so
x = 3