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Citrus2011 [14]
3 years ago
7

Which expression can be used to determine the length of segment ZY?

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

The length of segment ZY is of \sqrt{73} units.

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

In this question:

Point Z has coordinates (-5,1)

Pount Y has coordinates (3,4).

The length of segment ZY is the distance between points Z and Y. Thus

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

D = \sqrt{(-5-3)^2+(1-4)^2}

D = \sqrt{8^2+3^2}

D = \sqrt{73}

The length of segment ZY is of \sqrt{73} units.

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Write an expression that equals 40. Include an exponent.
devlian [24]
Let's start making our expression.
Just take the number 40 and change it around.
40=49-9
That's a good start.
49 is equal to 7×7, or 7². 9 is equal to 3×3, or 3².
So we can also write this as
7^2-3^2
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Answer:

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Step-by-step explanation:

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adell [148]

SOLUTION:

Case: Hypothesis testing

Step 1: Null and Alternative hypotheses

\begin{gathered} H_0:\mu=P127.50 \\ H_1:\mu\leq P127.50 \end{gathered}

Step 2: T-test analysis

\begin{gathered} t=\frac{\hat{x}-\mu}{\frac{s}{\sqrt{n}}} \\ t=\frac{135-127.5}{\frac{75.25}{\sqrt{450}}} \\ t=2.144 \end{gathered}

Step 3: t-test with the significance level

\begin{gathered} t_{\alpha}=? \\ \alpha=0.05 \\ From\text{ }tables \\ t_{0.05}=1.654 \end{gathered}

Step 4: Comparing

t>t_{\alpha}

So tail to reject the null hypothesis. There is enough evidence at a 0.05 level of significance to claim that the mean spent is greater than P127.50.

Final answer:

Yes, there is evidence sufficient to conclude that the mean amount spent is greater than P127.50 per month at a 0.05 level of significance.

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Answer:

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Step-by-step explanation:

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4 years ago
the height of an experimental plant after x days can be represented by the formula 3(4x+2). The height of a second plant can be
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Answer:

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Step-by-step explanation:

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