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Citrus2011 [14]
3 years ago
7

Which expression can be used to determine the length of segment ZY?

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

The length of segment ZY is of \sqrt{73} units.

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

In this question:

Point Z has coordinates (-5,1)

Pount Y has coordinates (3,4).

The length of segment ZY is the distance between points Z and Y. Thus

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

D = \sqrt{(-5-3)^2+(1-4)^2}

D = \sqrt{8^2+3^2}

D = \sqrt{73}

The length of segment ZY is of \sqrt{73} units.

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-x - 3 = 5x - 1 is the line above recopied 
+x     = +x       
    -3   = 6x - 1 
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    - 2   = 6x 
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3 0
3 years ago
Ok, now i need help from 1-5, 20 points
ratelena [41]

1 = 8

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4=9

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5 0
4 years ago
8 +2/3 (6x + 30) = 80
amid [387]

Answer:

X=13

Step-by-step explanation:

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5 0
3 years ago
If x=-1, x^5+x+4+x^3+x
DedPeter [7]

Answer:

0

Step-by-step explanation:

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8 0
2 years ago
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Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Dale drove hom
IrinaK [193]

Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed  of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

7y = (y+18)5

7y = 5y + 90

7y - 5y = 90 (collection like terms)

2y = 90

Y = 45

Substitute for y in eqn 1 to get distance away from mountain

= 7y eqn 1

= 7×45

= 315 miles.

∴ Dale leave 315 miles from the mountains

4 0
3 years ago
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