4x + 2 - 3x + 5 - 2(x + 5) = (2x - 5) + (3x + 4)
4x + 2 - 3x + 5 - 2x - 10 = 2x - 5 + 3x + 4
4x - 3x - 2x + 5 + 2 - 10 = 2x + 3x - 5 + 4
- x - 3 = 5x - 1
-x - 3 = 5x - 1 is the line above recopied
+x = +x
-3 = 6x - 1
<span> +1 = + 1 </span>
- 2 = 6x
- 2/6 = 6x/6
- 1/3 = x, the answer
Answer:
X=13
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
0
Step-by-step explanation:
yeah-ya.............. right?
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains