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mart [117]
3 years ago
5

HCl, HC2H3O2, and H2SO4 are examples of

Chemistry
1 answer:
irina1246 [14]3 years ago
5 0
First of all, it must be noted that all these substances presented above are examples of compounds it that they are made of one or more elements that are present in fixed ratios. Then, it may also be noted that all of them contain H (hydrogen), this type of substances are ACIDS. 
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By definition, any substance that donates a proton is best defined as _________.
BabaBlast [244]
A proton is the same as an H+ ion, and Arrhenius acids are the ones that release H+ in solution, so the answer is A
8 0
3 years ago
How many molecules in 3.4 moles of NH4NO3?
aliya0001 [1]

There are  20.5 x 10^24 molecules are present in 3.4 moles of NH4NO3.

<h3>How many molecules in 3.4 moles of NH4NO3?</h3>

We know that one mole of a substance has  6.022 × 10²³ molecules so in 3.4 moles of NH4NO3, we have 20.5 x 10^24 molecules if we multiply the  6.022 × 10²³ with 3.4.

So we can conclude that there are  20.5 x 10^24 molecules are present in 3.4 moles of NH4NO3.

Learn more about mole here: brainly.com/question/15356425

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5 0
1 year ago
What were the results on Rutherford's goldfoil experiment
diamong [38]

Answer:

Explanation:

The relative massive alpha particles could go through the gold foil without being deviated of their trajectory or only small deviations due to the uniformity distribution positive charge of the protons.

4 0
3 years ago
What is the balanced equation for the reaction of a solution of sodium sulfate is mixed with strontium chloride?
natta225 [31]

Answer:

NaSO⁴(ads) ,ganadicate

6 0
3 years ago
At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume wil
Romashka [77]

Answer:

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 104 kPa

P_2 = final pressure of gas = 52 kPa

V_1 = initial volume of gas = 2.0m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 21.1^oC=273+21.1=294.1K

T_2 = final temperature of gas = -5.0^oC=273+(-5.0)=268 K

Now put all the given values in the above equation, we get:

\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}

V_2=3.64 m^3

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

3 0
2 years ago
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