Answer:
Substance B, boiling point of 105 °C
Explanation:
Non volatile substances have high boiling points
Answer: kinetic energy
Explanation: searched it up
Answer:
This is an oxidation-reduction (redox) reaction:
2 Ni0 - 4 e- → 2 NiII
(oxidation)
2 O0 + 4 e- → 2 O-II
(reduction)
Ni is a reducing agent, O2 is an oxidizing agent.
Answer:
The final dilution is 1:400
Explanation:
Let's analyze what we are told: we have an initial 1:5 dilution of protein lysate. This means that the initial solution (stock solution) was diluted 5 times. Then, from this dilution the student prepared another dilution taking 2 mL of the first dilution in 8 mL of water. This is the same as saying we took 1 mL of first dilution in 4 mL of water (the ratio is the same), so we now have a second 1:4 dilution of the first dilution (1:5). Finally, the student made a third 1:20 dilution, this means that the second dilution was further diluted 20 times.
So, to calculate the final dilution of protein lysate, we have to multiply all the dilution factors of every dilution prepared: in this case we have a final dilution of 1:20, this means we have a factor dilution of 20. But it was previously diluted 4 times, so we have a factor dilution of 20×4 = 80. However, this dilution was also previously diluted 5 times, so the new dilution factor is 80 × 5 = 400
This means that the final dilution of the compound was diluted a total of 400 times compared to the initial concentration of stock solution.
Answer: 3.7 x10−6 Mole per dm^3
Explanation:
pH is the negative logarithm of hydrogen ion concentration in a solution.
So, pH = - log(H+)
Since the solution has a pH of 5.43
5.43 = -log(H+)
To get hydrogen ion concentration, find the Antilog of 5.43
(H+) = Antilog (-5.43)
(H+) = 0.000003715
Then, 0.000003715 in standard form becomes 3.7 x10−6 M
Thus, the concentration of hydrogen ion in the solution is 3.7 x10−6 Mole per dm^3
