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mart [117]
3 years ago
5

HCl, HC2H3O2, and H2SO4 are examples of

Chemistry
1 answer:
irina1246 [14]3 years ago
5 0
First of all, it must be noted that all these substances presented above are examples of compounds it that they are made of one or more elements that are present in fixed ratios. Then, it may also be noted that all of them contain H (hydrogen), this type of substances are ACIDS. 
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A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20
notsponge [240]

P1 * V1 ÷ T1 = P2 * V2 ÷ T2  

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420  

30,144 * V2 = 22,680  

V2 = 22,680 ÷ 30,144  

The new volume is approximately 0.75 liter.

I hope I helped

5 0
3 years ago
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During the titration of a weak acid and a strong base, you would expect the ph at the endpoint of titration to be ____.
riadik2000 [5.3K]

Answer is: b. more than 7.

The endpoint is the point at which the indicator changes colour in a colourimetric titration and that is point when titration must stop.

For example, basic salt sodium acetate CH₃COONa is formed from the reaction between weak acid (in this example acetic acid CH₃COOH) and strong base (in this example sodium acetate NaOH).

Balanced chemical reaction of acetic acid and sodium hydroxide:

CH₃COOH(aq) + NaOH(aq) → CH₃COONa(aq) + H₂O(l).

Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base react quantitatively with each other.

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3 years ago
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How are you guys today? o.0
Lady_Fox [76]

Answer:

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2 years ago
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(chem) which is more concentrated: 45.0 grams of HCOOH dissolved in 189 mL of water or 1.5 moles of CH↓2COOH dissolved in twice
Liula [17]

Answer:

CH3COOH would be more concentrated

Explanation:

The higher the concentration value, the more concentrated it is.

The relationship between concentration, moles and volume is given by the equation;

Concentration = No of moles / Volume

5.0 grams of HCOOH dissolved in 189 mL of water

Number of moles = Mass / Molar mass = 5 / 46.03 = 0.1086 mol

Concentration = 0.1086 / 0.189 = 0.5746 mol/L

1.5 moles of CH3COOH dissolved in twice as much water

Volume = 2 * 189 = 378 ml = 0.378 L

Concentration = 1.5 / 0.378 = 3.9683 mol/L

Comparing both concentration values;

CH3COOH would be more concentrated

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3 years ago
A particular uranium alloy has a density of 18.75 g/cm3.
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