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3 years ago

Brainiest plsss helpp

Chemistry

2 answers:

djyliett [7]3 years ago

8 0

Answer:

b 13kg/m³ is the answer to this question

Marina86 [1]3 years ago

6 0

Answer:

A) 19320 kg/m^3

Explanation:

hope this helps and please give me brainiest if i get it correct or if you want? i would be happy if you did :D

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the freezing point depression constants of the solvents cyclohexane and naphthalene are 20.1°C/m and 6.94°C/m respectively. Whic

Evgesh-ka [11]

Explanation:

It'd be better to use cyclohexane. The possible explanation is that the freezing temperature will change by 20.1 degrees for each mole of substance added to 1 kg of cyclohexane, although the same amount added to naphthalene will change its freezing point just by 6.94 degrees.

It is so much easier to identify a larger change more adequately than a smaller one. You would actually not have a 1 molal solution in operation, so the variations in freezing points would be even smaller than the ones already described.

7 0

3 years ago

Which is a spectator ion in the reaction between these two solutions babr2 + na2so4?

Greeley [361]

Spectator ion are ions which remain unchanged during chemical equation and does not affect equilibrium
chemical equation for the reaction is as follows
NaSO4 +Babr2 ---> 2 Nabr + BaSO4
ionic equation is as follows
Ba ^+2 + SO^-2 --->BaSO4(s)
therefore the spectator ion are Na+ and Br- ions

6 0

4 years ago

Read 2 more answers

What is the difference between alkane and alkene???

valentina_108 [34]

Answer:

the basic difference btw alkane and alkene is the presence of single and double bond respectively.first is saturated hydrocarbon while the latter is unsaturated

Hope this helps you buddy!!

4 0

3 years ago

Read 2 more answers

The following statements all describe changes in matter. Some of these changes are physical, and some are chemical. Select the s

GenaCL600 [577]

The change of the statue of liberty from copper to green is an example of a chemical change.

<h3>Physical and chemical change</h3>

A physical change does not involve the formation of new substances and the composition of the substance does not change. However, in a chemical change, a new substance is formed and the composition of the substance changes.

The statement that reflect a chemical change is;

The Statue of Liberty’s metal tarnishes from copper to green.

Learn more about physical and chemical change: brainly.com/question/13316655

8 0

2 years ago

A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.

Alexxandr [17]

Answer: The empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

Explanation:

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = $\frac{0.313}{0.078}=4.01\approx 4$

For Hydrogen = $\frac{0.316}{0.078}=4.05\approx 4$

For Oxygen = $\frac{0.078}{0.078}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is $C_4H_4O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

$n=\frac{130g/mol}{68g/mol}=1.9\approx 2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2$

Hence, the empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

4 0

3 years ago