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Marta_Voda [28]
3 years ago
13

Hi‍‍‍♀️‍♀️‍‍♀️‍♀️‍‍‍‍♀️‍♀️‍♀️‍‍‍♀️‍‍♀️‍‍‍‍‍♀️‍♀️‍‍‍‍‍‍‍❤️‍‍‍‍‍‍‍‍‍‍‍‍‍‍❄️

Mathematics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

heyyyyy <3

Step-by-step explanation:

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15-18, use the properties of the exponents to write an equivalent expression for each given expression.
Leto [7]

15.

( {4}^{4} ) {}^{3}

=  {4}^{4 \times 3}

=  {4}^{12}

= 16777216

___________________________________________

16.

\frac{ {3}^{12} }{ {3}^{3} }

=  {3}^{12 - 3}

=  {3}^{9}

= 19683

___________________________________________

17.

{4}^{5}  \times  {4}^{2}

=  {4}^{(5 + 2)}

=  {4}^{7}

= 16384

___________________________________________

18.

{6}^{4}  \times  {2}^{4}

=  ({6 \times 2})^{4}

=  {12}^{4}

= 20736

6 0
3 years ago
This one too! Thank you so much
denis23 [38]

2(l+w)=P\ \ \ \ |:2\\\\l+w=\dfrac{P}{2}\ \ \ \ \ |-l\\\\\boxed{w=\dfrac{P}{2}-l}

8 0
3 years ago
Two polls were conducted about the upcoming election for new governor. The first poll said that 45% of the people asked would vo
castortr0y [4]

Answer:

A. Yes, the two corresponding confidence intervals overlap.

Step-by-step explanation:

The correct option is - A. Yes, the two corresponding confidence intervals overlap.

Reason -

P(1) = 45% = 0.45

E(1) = 4.6% = 0.046

Confidence Interval = P(1) ± E(1)

                                 = 0.45 ± 0.046

So, the interval is -

0.45 + 0.046 ≤ P ≤ 0.45 - 0.046

⇒0.496 ≤ P ≤ 0.404                       .............(1)

Now,

P(2) = 42% = 0.42

E(2) = 3.6 % = 0.036

Confidence Interval = P(2) ± E(2)

                                 = 0.42 ± 0.036

So, the interval is -

0.42 + 0.036 ≤ P ≤ 0.42 - 0.036

⇒0.456 ≤ P ≤ 0.384                    ...............(2)

From equation (1) and (2), we get

The two corresponding confidence intervals overlap.

6 0
3 years ago
Wants the weight of one dose
DerKrebs [107]
You cannot really weigh a dose. 
8 0
3 years ago
Help help help help help help help help help help help
kvasek [131]

Solving the quadratic equation we conclude that:

  • The maximum height is 45ft.
  • The rocket is 18 seconds in the air.

<h3>How to get the maximum height of the rocket?</h3>

The height of the rocket is defined by the quadratic equation:

d = 90t - 5t^2

The maximum height is what we get in the vertex of the quadratic equation, such that for this quadratic equation, the vertex is at:

t = -90/(2*-5) = 9

So the maximum height is what we get when we evaluate in t = 9:

d = 90*9 - 5*9^2 = 45

The maximum height is 45ft.

<h3>How to get the time in the air?</h3>

Now we need to solve the equation for the largest value of t:

d = 90*t - 5t^2 = 0

Rewriting it, we get:

0 = 90*t - 5*t^2\\\\0 = t*(90 - t*5)

The maximum solution is what we get when:

0 = 90 - t*5

t = 90/5 = 18

The rocket is 18 seconds in the air.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
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