For this case we must indicate which of the equations shown can be solved using the quadratic formula.
By definition, the quadratic formula is applied to equations of the second degree, of the form:
Option A:
Rewriting we have:
This equation can be solved using the quadratic formula
Option B:
Rewriting we have:
It can not be solved with the quadratic formula.
Option C:
Rewriting we have:
This equation can be solved using the quadratic formula
Option D:
Rewriting we have:
It can not be solved with the quadratic formula.
Answer:
A and C
Hello!
If you want to find an equation that is parallel to another equation, and passing through the point (1, 4), you need to create a new equation with the same slope, you need to substitute the given point into the new equation to find the y-intercept.
m = 3, y = 3x + b (substitute the ordered pair)
4 = 3(1) + b (simplify)
4 = 3 + b (subtract 3 from both sides)
b = 1
Therefore, the line parallel to the line y = 3x - 2 and passing through the point (1, 4) is y = 3x + 1.
Answer:
I believe the answer is B.
Step-by-step explanation:
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Answer:
(b) a trapezoid
Step-by-step explanation:
A graph of the points reveals one pair of parallel sides: a trapezoid.
