An original sample of K-40 has a mass of 25.00 grams.
After 3.9 m 109 years, 3.125 grams of the original sample remains unchanged.
What is the half-life of K-40?
First step is to determine the remaining decimal amount.
3.125 grams /25.00 grams = 0.125
Second step is to determine the number of half lives.
(1/2)^n = 0.125
N log (1/2) = log 0.125
N = 3 years
Hey there!
Get molar mass of C₆H₁₀S:
C: 6 x 12.01
H: 10 x 1.008
S: 1 x 32.065
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144.205 g
To find the amount of moles we have, divide 22.4 by 144.205. Get 0.155.
There are 0.155 moles of S.
Hope this helps!
a. cesium and sulfur would be an ionic bond (metal + non-metal)
b. chlorine and bromine would be a covalent bond (non-metal+ non-metal)
c. magnesium and fluorine would be ionic again (metal + non-metal)
d. silver and mercury would be a metallic bond I'm pretty sure at least (metal+metal)
By measuring them, by monitoring them, or by separating them.
Answer:
im confused on what you mean
Explanation:
