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Lynna [10]
4 years ago
11

Less dense then gas

Chemistry
1 answer:
Slav-nsk [51]4 years ago
4 0
Nothing is less dense than gas. gas is the least dense form of matter.
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a motorcycle is moving along a road for a distance of 20KM. After 2 hours what is it's the average speed?
JulijaS [17]

Answer:

If it took the motorcycle 2 hours to cover 20km, then the average speed is 10km per hour.

Explanation:

Speed is equal to distance over time. So 20km divided by 2 hours is 10 km per hour.

Please mark brainliest!!! Thanks.

6 0
3 years ago
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Unit Test
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Heat flows from faster molecules to slower molecules when they collide.

Explanation:

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A balanced chemical reaction obeys the law of...
tia_tia [17]
Its c.  Not a 100% sure 
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3 years ago
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Which of the following is TRUE?
stiks02 [169]

Answer:

Explanation:

For a general equilibrium

aA +bB ⇔ cC + dD ,

the equilibrium constant is K = [C]^c [D]^d / [A]^a[B]^b.

Our reasoning here should be based on the fact that  Q has the same expression as K, but is used when the system is not at equilibrium, and the system will react to make Q = K to attain it ( Le Chatelier´s principle ).

So with this in mind, lets answer this question.

1. False: Q can large or small but is not the value of the equilibrium constant, it will predict the side towards the equilibrium will shift to attain it.

2. False: Given the expression for the equilibrium constant, we know if K is small the concentrations of the reactants will be large compared to the equilibrium concentrations of the products.

3. False: when the value of K is large, the equilibrium concentrations of the products will be large and it will lie on the product side.

4. True: From our previous reasongs this is the true one.

5. False: If K is small, the equilibrium lies on the reactants side.

8 0
3 years ago
What would the percentage of thorium-232 (parent compound) be in a rock that was dated at 2.8 billions years?
just olya [345]

The half-life of Th-232 is 1.405 × 10¹⁰ years  

Time elapsed = 2.8 x 10⁹ years  

Equation of radioactive decay:

A = A₀ = (1/2)^ t/t₁/₂

where A₀ is the initial amount, A is the amount after time t, t₁/₂ is the half file

The fraction of thorium-232 that remains in the rock after 2.8 billions years is,

A/A₀ = (1/2) ^ (2.8 x 10⁹/ 1.405 × 10¹⁰) = 0.871

Therefore, the percentage of thorium-232 in the rock that was dated at 2.8 billions year = 87.1%


5 0
4 years ago
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