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aivan3 [116]
3 years ago
15

Please help will give brainliest

Mathematics
2 answers:
astraxan [27]3 years ago
7 0
The answer is a circle
Eddi Din [679]3 years ago
6 0

Answer:

circle

Step-by-step explanation:

please mark brainliest

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Solve the equation for x by graphing.-4x-1 5x=4
Gemiola [76]

Answer: Undefined

Step-by-step explanation:

slope is undefined

no y intercept

This line is vertical

4 0
3 years ago
In the expression 2003-02-02-00-00_files/i0020000, the number 4 is called the __________.
elixir [45]
Base is the correct answer
5 0
3 years ago
Write three ordered pairs for direct variation relationship where y= 12 when x= 16
Kruka [31]

Ordered pairs that work for this direct variation are (4, 3), (8, 6) and (12, 9).

In order to find these, we must first find the value of the direct variation coefficient. We can do that using the base equation y = kx and then by plugging in to find k.

y = kx

12 = k(16)

3/4 = k

Now that we have k, we can model the equation as y = 3/4x. We can also find any number of ordered pairs by using the x value and finding the y value. All of the above answers work.

3 0
3 years ago
Beth has only 20p and 10p coins in her purse.
marta [7]

Answer:

non lo so

Step-by-step explanation:

5 0
2 years ago
Evaluate the integral ∫2−1|x−1|dx
defon

I think you might be referring to the definite integral,

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx

Recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

Then |x-1|=x-1 if x\ge1, and |x-1|=1-x is x. So spliting up the integral at <em>x</em> = 1, we have

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx

The rest is simple:

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}

5 0
3 years ago
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