Answer:
I cant see the whole question but to my knowledge it is the 3rd law
Explanation:
because the third law states what the applied force is when two objects interact
Answer:
1.0
Explanation:
Hydrochloric acid is a strong acid, that is, an acid that dissociates completely, according to the following reaction.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
Then, the concentration of H⁺ will be equal to the initial concentration of the acid, i.e., 0.10 M.
We can calculate the pH using the following expression.
pH = -log [H⁺] = -log 0.10 = 1.0
Answer:
Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.
Explanation:
- It is a stichiometry problem.
- We should write the balance equation of the mentioned chemical reaction:
<em>2Al + 3CuCl₂ → 3Cu + 2AlCl₃.</em>
- It is clear that 2.0 moles of Al foil reacts with 3.0 moles of CuCl₂ to produce 3.0 moles of Cu metal and 2.0 moles of AlCl₃.
- Also, we need to calculate the number of moles of the reported masses of Al foil (0.50 g) and CuCl₂ (0.75 g) using the relation:
<em>n = mass / molar mass</em>
- The no. of moles of Al foil = mass / atomic mass = (0.50 g) / (26.98 g/mol) = 0.0185 mol.
- The no. of moles of CuCl₂ = mass / molar mass = (0.75 g) / (134.45 g/mol) = 5.578 x 10⁻³ mol.
- <em>From the stichiometry Al foil reacts with CuCl₂ with a ratio of 2:3.</em>
∴ 3.85 x 10⁻³ mol of Al foil reacts completely with 5.578 x 10⁻³ mol of CuCl₂ with <em>(2:3)</em> ratio and CuCl₂ is the limiting reactant while Al foil is in excess.
- From the stichiometry 3.0 moles of CuCl₂ will produce the same no. of moles of copper metal (3.0 moles).
- So, this reaction will produce 5.578 x 10⁻³ mol of copper metal.
- Finally, we can calculate the mass of copper produced using:
mass of Cu = no. of moles x Atomic mass of Cu = (5.578 x 10⁻³ mol)(63.546 g/mol) = 0.354459 g ≅ 0.36 g.
- <u><em>So, the answer is:</em></u>
<em>Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.</em>
Explanation:
Given parameters:
Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole
Unknown:
Mass of the sulfur trioxide = ?
Solution:
To solve for the mass of the sample of sulfur trioxide:
- Find the molar mass of the compound i.e SO₃
atomic mass of S = 32g
O = 16g
molar mass = 32 + 3(16) = 80g/mol
mass of SO₃ = number of moles x molar mass
mass of SO₃ = 1.55 x 10³ x 80 = 124000g or 124kg
Learn more:
mole calculation brainly.com/question/13064292
#learnwithBrainly
Given that <span>sample a has a higher melting point than sample
b. Therefore, sample a is a longer chain of a </span><span>fatlike solid substance. It could also be that the bonds present in sample a is much stronger which will require more energy to break. Hope this answers the question.</span>
