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Lana71 [14]
3 years ago
14

For the chemical reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many moles of lead(II) iodide (PbI2) are produced from 8.0 mol of potassiu

m iodide (KI)? number of moles: mol
Chemistry
1 answer:
Mashcka [7]3 years ago
7 0

Answer:

the number of moles is 6

Explanation:

The computation of the number of moles is given below:

According to the question

Since 2 mol of KI produces 1 mol of PbI2

based on the above information  

The number of moles would be  

8 mol will produce 6 mol of PbI2

Therefore the number of moles is 6

Hence, the same is considered and relevant too

The other things would be ingored

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when washing soda is mixed with lemon juice, bubbles are formed with the evolution of gas. what type of change is it. ​
aleksandr82 [10.1K]

Answer:

it is a chemical change

Explanation:

it is a chemical change since the lemon juice can not be returned to its original form some part of it had been converted to gas form

3 0
3 years ago
A intramuscular medication is given at 5.00mg/kg of body weight. What is the dose in grams for a 180-lb patient?
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0.408 gram for 180-lb patient
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4 years ago
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What is the frequency of a light that has a wavelength of 3.0 x 10 -7m?
alexdok [17]

Answer:

 frequency of light (f) = 1 x 10¹⁵s⁻¹

Explanation:

Given Data:

Wavelength of light λ = 3.0 x10⁻⁷m

Frequency of light: to be calculated

Formula Used to find frequency:

                                  f = V/λ ........................... (1)

where

f is the frequency

V is the velocity

λ is wavelength

Velocity of light = 3 x 10⁸ ms⁻¹

put the values in equation (1)

                                     f =  3 x 10⁸ ms⁻¹ / 3.0 x10⁻⁷m

                                     f = 1 x 10¹⁵s⁻¹

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7 0
3 years ago
A 6.165 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 10.27 grams of CO2 and 3
e-lub [12.9K]

Answer:

Explanation:

mass of carbon in 10.27 g of CO₂ = 12 x 10.27 / 44 = 2.80 g

mass of hydrogen ( H ) in 3.363 g of H₂O = 2  x 3.363 / 18

= .373 g

These masses would have come from the sample of 6.165 g .

Rest of 6.165 g of sample is oxygen .

So oxygen in the sample = 6.165 - ( 2.8 + .373 ) = 2.992 g

Ratio of C  , H , O in the sample

2.8 : .373 : 2.992

C: H : O : : 2.8 : .373 : 2.992

Ratio of moles

C: H : O : : 2.8/12 : .373/1 : 2.992 / 16

C: H : O : : .2333 : .373 : .187

C: H : O : : .2333/.187 : .373/.187 : .187/.187

C: H : O : : 1.247 : 1.99 : 1

C: H : O : : 5 : 8 : 4 ( after multiplying by 4 )

Hence empirical formula

C₅H₈O₄

Molecular formula ( C₅H₈O₄ )n

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