Calculate the number of moles from the given number of particles. Express your answer to the correct number of significant figur
2 answers:
Answer:
The answer is 2.09 moles
Explanation:
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.
Then you can apply a rule of three as follows: if 6.023*10²³ particles are contained in 1 mole, 1.26*10²⁴ particles in how many moles are they?
moles= 2.09
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Answer:
Explanation:
First thing is we have assume all the percents are grams so we have
68.279g C, 6.2760g H, 3.7898g N, and 21.656g O
Now convert each gram to moles by dividing the the molar mass of each element
68.279g/12.01g= 5.685 moles of C
6.2760g/1.01g= 6.214 moles of H
3.7898g N/14.01g= 0.271 moles of N
21.656g O/ 16.00g= 1.354 moles of O
Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....
5.685 moles/0.271 moles ------> ~21 C
6.214 moles/0.271 moles --------> ~23 H
0.271 moles / 0.271 moles ---------> 1 N
1.354 moles/ 0.271 moles ----------> ~5 O
So the empirical formula is C21H23NO5
Answer:
Velocity, u = 14.7 m/s
Explanation:
It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.
Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms
Using first equation of kinematics as :
In case of crash the final speed of the driver is, v = 0
u = 14.7 m/s
So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.