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Airida [17]
3 years ago
13

In the laboratory a student finds that it takes 103 Joules to increase the temperature of 12.6 grams of solid diamond from 22.4

to 39.4 degrees Celsius. The specific heat of diamond calculated from her data is
Chemistry
1 answer:
Mazyrski [523]3 years ago
4 0

Answer:

The correct solution is "0.480 \ J/g^{\circ}C".

Explanation:

Given:

q = 103 J

Mass,

m = 12.6 grams

Temperature,

T_1=22.4

T_2=39.4

\Delta T=T_2-T_1

      =39.4-22.4

      =17^{\circ}C

Now,

⇒  C=\frac{q}{m\times \Delta T}

⇒      =\frac{103}{12.6\times 17}

⇒      =\frac{103}{214.2}

⇒      =0.480 \ J/g^{\circ}C

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Which metal atom below would Not be involved in formation of a Type II Compound?
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Read 2 more answers
A gas that effuses through a porous cylinder 1.87 times faster than chlorine gas. what is the molar mass and identity.
Rufina [12.5K]
From the Graham's law of effusion;
R1/R2 = √MM2/√MM1
Molar mass of chlorine gas is 71
Therefore;
1.87= √ 71 /√mm1
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4 years ago
a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
zhannawk [14.2K]
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

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The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!
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4 years ago
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