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zheka24 [161]
3 years ago
6

Consider the following reaction:

Chemistry
1 answer:
slava [35]3 years ago
5 0

Answer:

Option D is correct =  58 g

Explanation:

Data Given:

mass of LiOH = 120 g

Mass of Li3N= ?

Solution:

To solve this problem we have to look at the reaction

Reaction:

                  Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)

                    1 mol                                                      3 mol

Convert moles to mass

Molar mass of LiOH = 24 g/mol

Molar mass of  Li₃N = 35 g/mol

So,

                   Li₃N (s)        +     3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)

                1 mol (35 g/mol)                                                   3 mol (24 g/mol)

                   35 g                                                                         72 g

So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of  LiOH

For this apply unity formula

                        35 g of  Li₃N ≅ 72 g of LiOH

                        X of  Li₃N ≅ 120 g of LiOH

By Doing cross multiplication

                  Mass of Li₃N = 35 g x 120 g / 72 g

                   mass of Li₃N =  58 g

120 g of LiOH will produce from 58 g of Li₃N

So,

Option D is correct =  58 g

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a student prepares a dilute solution of sodium hydroxidem, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.
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Answer:

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Explanation:

As I said in the comments, you are missing the required volume of the base to react with the KHP. I found this on another site, and the volume it used was 21.84 mL.

Now, KHP is a compound often used to standarize NaOH or KOH solutions. This is because it contains a mole ratio of 1:1 with the base, so it's pretty easy to use and standarize any base.

Now, as we are using an acid base titration, the general expression to use when a acid base titration reach the equivalence point would be:

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Now, we also know that moles can be expressed like this:

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And according to this, we are given the volume of base and the required mass of KHP. So, if we want to know the concentration of the base, we need to get the moles of the KHP, because in the equivalence point, these moles are the same moles of base.

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