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Mrrafil [7]
3 years ago
9

PLS HELP!! THANK UU ILL APPRECIATE IT PLS

Mathematics
2 answers:
Ludmilka [50]3 years ago
4 0

Answer:

56 pound ...,...........

IgorC [24]3 years ago
3 0
I think it’s 56 pounds
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Which of the following graphs represents a function choose all that apply
melisa1 [442]

Answer:

where the graphs?

Step-by-step explanation:

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38. Jean owes her parents $90, to be paid in 5 equal installments. How much is each<br> installment?
creativ13 [48]
90 divided by 5 is 18 so $18 is the answer
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3 years ago
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Identify the horizontal asymptote of f(x) = quantity 2 x minus 1 over quantity x squared minus 7 x plus 3.
Rina8888 [55]
We must recall that a horizontal asymptote is the value/s of y that the given function approaches to but never reaches. To find this in a rational function, we compare the expressions with highest degree in the numerator and denominator. There are three possible outcome when this happens.

1. if the highest degree (highest exponent) in the numerator is bigger than that of the denominator, then there won't be any horizontal asymptote.

2. if the highest degree in the denominator is bigger, then the horizontal symptote would be y = 0.

3. if they have the same highest degree, then we just get the quotient of their coefficient. 

Now, going back to our function, we have

f(x) = \frac{2x - 1}{x^{2} - 7x + 3}

From this we can see that the highest degree in the numerator is 1 (from 2x) and 2 (from x²) for the denominator. Clearly, it shows that its denominator has a higher degree. And from our discussion, we can conclude that the horizontal asymptote would be y = 0.

Answer: y = 0
3 0
4 years ago
How would you combine the area of the top circle, bottom circle, and rolled-out the cylinder to make the total surface area?
aliya0001 [1]

Answer:

The total surface area of a cylinder is equal to the sum of areas of all its faces. The total surface area with radius ‘r’, and height ‘h’ is equal to the sum of the curved area and circular areas of the cylinder.

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2 years ago
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liq [111]

Answer:

a) 18

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Step-by-step explanation:

a) What are the degrees of freedom for Student's t distribution when the sample size is 19?

Degrees of freedom = n - 1

Where n = sample size

= 19 - 1

= 18

b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.

(Round your answer to three decimal places.)

We would be determining these using the t distribution table

1 - 0.95 = 0.05 ( for two tailed)

Or

0.05/2 = 0.025(one - tailed)

Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101

7 0
4 years ago
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