I wonder if you mean to write ![\sqrt[3]{256}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D)
in place of 
...
If you meant what you wrote, then we have
If you meant to write (the cube root of 256), then we could go on to have
![\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D%3D%5Csqrt%5B3%5D%7B16%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E2%29%5E2%7D%3D%5Csqrt%5B3%5D%7B4%5E4%7D%3D%5Csqrt%5B3%5D%7B4%5E3%5Ccdot4%7D%3D4%5Csqrt%5B3%5D4)
I think the answer would be the 0.039.
Answer:
13 cups
Step-by-step explanation:
If the small box has 10 cups, then:
<u> (small) </u> <u> 10 cups </u> = <u> 100% </u>
(medium) x cups = 130%
Now, cross multiply:
10 (130) = x (100)
1300 = 100x
x = 13
Another way to solve this is by turning 30% into a decimal:
30/100 = 0.3
10 (0.3) = 3
Now you have 30% of the 10 cups, but you need <u>30% more</u><em> </em>than the small box, so:
10 + 3 = 13 cups
Answer:
Step-by-step explanation:
3*√6 + 2√24 + 7√54= P
3√6 + 2√2*2*6 + 7√3*3*6
3√6 + 2*2√6+7*3√6
3√6 + 4√6 + 21√6
28√6 = the perimeter.
