Answer:
1.52M in NaCl
Explanation:
Molarity = moles solute / volume solution in Liters
=> molarity (M) = 3.8 moles / 2.5 Liters solution = 1.52 molar solution in NaCl
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A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the
solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.
The first law says that an object at rest tends to stay at rest, and an object in motion tends to stay in motion, with the same direction and speed. Motion (or lack of motion) cannot change without an unbalanced force acting. If nothing is happening to you, and nothing does happen, you will never go anywhere.
Answer:
The correct answer is (B) 0.50 g/mL
Explanation:
The density of a subtance is equal to the ratio between its mass and its volume, as follows:
d = m/v
In the problem, the mass is equal to 80.0 g. The volume is given by the increment in volume in the graduated cylinder when the solid is placed because the solid is insoluble so it displaces the liquid and increases the volume. The initial volume was 40.0 ml and the final volume was 80.0 ml, so:
V = Final volume - initial volume = 80.0 ml - 40.0 ml = 40.0 ml
Finally, we calculate the density by dividing the mass into the volume:
