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coldgirl [10]
3 years ago
7

What is an Independent Variable (IV)? *

Chemistry
1 answer:
worty [1.4K]3 years ago
8 0

here's your answer dear friend❤❤

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A prostate might be prescribed a total dose ionizing radiation of 72 Gy. In traditional units of rad, how many rad have been pre
weeeeeb [17]

Answer:

7200RAD

Explanation:

Note

100RAD=1GY

Hence 72GY=7200RAD

8 0
3 years ago
Explain 2 reasons why SI is easier to use than the English System
11111nata11111 [884]

There's only one unit for each type of measurement in the SI. For example:

1)Regarding distance, in the SI there are meters and that's it; everything else is just a power of ten. On the other hand, the US Customary system has mils, inches, feet, yards, rods, furlongs, miles, nautical miles and leagues, with strange conversion factors between them all.

2)For volume, in the SI, there are liters and that's it; everything else is just a power of ten. On the other hand, the US Customary system has drams, teaspoons, tablespoons, ounces, gills, cups, pints, quarts, gallons, pecks, bushels, drums, beer barrels, liquid barrels, whiskey/kerosene barrels, oil barrels, cubic inches, cubic feet, cubic yards and I don't know of anyone who can remember the conversion factors for all those units! Oh--don't forget--a dry pint, quart, gallon or barrel is not the same thing as a fluid pint, quart, gallon or barrel, respectively.

3 0
3 years ago
Arrange the following in order of increasing bond strength of the carbon oxygen bond: Group of answer choices Carbon monoxide &l
Irina-Kira [14]

Answer:

carbonate ion < carbon dioxide < carbon monoxide

Explanation:

Bond strength depends on the bond order of a bond. The higher the bond order, the greater the bond strength since shorter bonds are stronger than longer bonds.

The carbonate ion has a bond order of 1.33, carbon dioxide has a bond order of 2 while carbon monoxide has a bond order of 3.

Since the compound with the highest C-O  bond order has the strongest C-O bond, then carbon monoxide possesses the strongest C-O bond.

3 0
3 years ago
Calculate the number of molecules in 0.54 grams of Ca(NO3)2
Volgvan

Explanation:

We have to find the number of molecules that are present in 0.54 g of Ca(NO₃)₂.

First we have to convert the mass of our sample into moles of Ca(NO₃)₂. We will use the molar mass of Ca(NO₃)₂ to do that.

molar mass of Ca = 40.08 g/mol

molar mass of N = 14.01 g/mol

molar mass of O = 16.00 g/mol

molar mass of Ca(NO₃)₂ = 1 * 40.08 g/mol + 2 * 14.01 g/mol + 6 * 16.00 g/mol

molar mass of Ca(NO₃)₂ = 164.10 g/mol

mass of Ca(NO₃)₂ = 0.54 g

moles of Ca(NO₃)₂ = 0.54 g * 1 mol/(164.10 g)

moles of Ca(NO₃)₂ = 0.00329 moles

According to Avogadro's number there are 6.022 *10^23 molecules in 1 mol of molecules. We can use that relationship to find the number of molecules that are present in our sample.

6.022 *10^23 molecules = 1 mol

molecules of Ca(NO₃)₂ = 0.00329 moles * 6.022 *10^23 molecules/(1 mol)

molecules of Ca(NO₃)₂ = 2.0 * 10^21 molecules

Answer: there are 2.0 * 10^21 molecules of Ca(NO₃)₂ in 0.54 g of it.

5 0
1 year ago
How many atoms are in a sample of 1.83 moles of potassium atoms
Sveta_85 [38]

Answer:  3.29 × 1023 atoms

3 0
4 years ago
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