ANSWER
Find out the how many pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.
To proof
As given
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9.
the total part of the alloy are 18.
assuming one part be x.
thus
nickel part = 2x
zinc part = 7x
copper part = 9x
alloy that contains 4.9 lb of zinc.
than the equation becomes
7x = 4.9
x = 0.7
Therefore
nickel part = 2x
= 2× 0.7
= 1.4 lb
1.4 lb of nickel have to be used to create alloy that contains 4.9 lb of zinc.
Hence proved
Answer:
The first step is
Take the square root of both sides of the equation
Step-by-step explanation:
we have
Solve for x
step 1
Take square root both sides
the solutions are
and 
therefore
The first step is
Take the square root of both sides of the equation
Answer:
Obtuse
Step-by-step explanation:
Right = has angle measure of 90°
Acute = has angle measure less than 90°
Equilateral = 2 or more angles whose angle measures are congruent to others
Circle = measures 360°
<u>Obtuse = Angle measure greater than 90° and less than 180°</u>
Hope this helps!
Answer: 7.527 oz
Step-by-step explanation: 78%= 0.78
Mass of gold is 0.78 · 9.65 oz = 7.527 oz
Answer:
1) = 32.02
2) = 18
Step-by-step explanation:
1) 20^2 + 25^2 = 1025
sq rt 1025 = 32.02
2) 30^2 - 24^2 = 324
sq rt 324 = 18
