The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,
Mass of Fe = 227.8 g
Moles of Fe = 
Mass of oxygen = 128 g
Moles of 
Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.
Mass of iron (III) oxide produced from Iron = 
Mass of iron (III) oxide produced from oxygen=
Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.
Hey there!
Magnesium chlorate: Mg(ClO₃)₂
Find molar mass.
Mg: 1 x 24.305 = 24.305
Cl: 2 x 35.453 = 70.906
O: 6 x 16 = 96
------------------------------------
191.211 g/mol
We have 187.54 grams.
187.54 ÷ 191.211 = 0.9808
There are 0.9808 moles in 187.54 grams of magnesium chlorate.
Hope this helps!
Answer:
(a) 0.047 g (b) 0.0016 oz (c) 0.0001 lb
Explanation:
The given mass of the sodium in the slice = 47 mg
(a) Mass has to be calculated in grams
The conversion of mg to g is shown below as:
1 mg = 10⁻³ g
So,
<u>Mass of sodium = 47 × 10⁻³ g = 0.047 g</u>
(b) Mass has to be calculated in ounces
The conversion of ounces to g is shown below as:
453.6 g = 16 oz
Or,
1 g = 16 / 453.6 oz
So,
<u>Mass of sodium = (0.047 × 16) / 453.6 oz = 0.0016 oz</u>
(c) Mass has to be calculated in pounds
The conversion of pounds to g is shown below as:
1 lb = 453.6 g
Or,
1 g = 1/ 453.6 lb
So,
<u>Mass of sodium = (0.047 × 1) / 453.6 oz = 0.0001 lb</u>
