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user100 [1]
3 years ago
8

Aaron travels 125 miles in 2.5 hours. At this rate, how far will he be able to travel in 6 hours?

Mathematics
1 answer:
Serga [27]3 years ago
3 0

Answer:

I believe it is 687.5 miles

Step-by-step explanation:

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!!!!NEED HELP ASAP!!!! NO LINKS OR REPORT
Pie

Hi there!

\large\boxed{2, -9}

We can create an equation for the line PR using the given coordinates. Use the following formula for the slope:

m = \frac{y_2-y_1}{x_2-x_1}

Plug in the coordinates for P and R:

m = \frac{-5-(-1)}{-1-(-4)} = -\frac{4}{3}

Find the equation by using point-slope form:

y - y1 = m(x - x1)

Plug in a coordinate and the slope:

y - (-5) = -4/3(x - ( - 1))

Simplify:

y + 5 = -4/3(x + 1)

To find the y-coordinate if x = 2, plug in the x value:

y + 5 = -4/3(2 + 1)

y + 5 = -4/3(3)

y + 5 = -4

y = -9

Thus, the coordinate is (2, -9)

6 0
3 years ago
Clara asked her coworkers about how much time they spent commuting each morning. This box-and-whisker plot shows the results.
blondinia [14]
I think the 40 30 20 should be going up not down like this 20 30 40 
6 0
3 years ago
The radius of the base of the cylinder is 2x cm and the height of the cylinder is h cm.
valentina_108 [34]

Answer:

h = 9x

Step-by-step explanation:

Given: i. for the cylinder, base radius = 2x cm, height = h cm

           ii. for the sphere, radius = 3x cm

           iii.  volume of the cylinder = volume of the sphere

volume of a cylinder is given as;

volume = \frac{1}{3}\pir^{2}h

where: r is its base radius and h the height

volume of the given cylinder = \frac{1}{3}\pi x (2x)^{2} x h

                                              = \frac{1}{3}\pi x 4x^{2} x h

                                              = \frac{4}{3}\pix^{2} h

volume of a sphere = \frac{4}{3}\pir^{3}

where r is the radius.

volume of the given sphere =  \frac{4}{3}\pi x (3x)^{3}

                                         =  \frac{4}{3}\pi x 9 x^{3}

                                         = 12\pix^{3}

Since,

volume of the cylinder = volume of the sphere

Then we have;

\frac{4}{3}\pix^{2} h = 12\pix^{3}

4\pix^{2} h = 36\pix^{3}

subtract x^{2} from both sides

4\pih = 36\pix

divide both sides by 4\pi

h = \frac{36\pi x}{4\pi }

  = 9x

h = 9x

5 0
3 years ago
3a-4b=12 what does a solve?
leonid [27]

Answer:

a = 4 + -1.333333333b

Step-by-step explanation:

Simplifying

3a + 4b = 12

Solving

3a + 4b = 12

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4b' to each side of the equation.

3a + 4b + -4b = 12 + -4b

Combine like terms: 4b + -4b = 0

3a + 0 = 12 + -4b

3a = 12 + -4b

Divide each side by '3'.

a = 4 + -1.333333333b

Simplifying

a = 4 + -1.333333333b

8 0
3 years ago
I need help i don’t understand
ch4aika [34]

9514 1404 393

Answer:

  A) J(-3, 1), ...

Step-by-step explanation:

All of the answer choices list point J' first, so it is convenient to use that as an example.

Point J on the given graph has coordinates (x, y) = (3, 2). The x-coordinate is 3 because the point is 3 units to the right of the y-axis.

The problem statement tells you to translate this point 6 units to the left. When you move it 6 units left, it will move left 3 units to the y-axis, then left 3 more units to have an x-coordinate of 3 -6 = -3. That is, each unit of movement to the left subtracts 1 from the x-coordinate. The x-coordinate of J is 3, so the final point J' will have an x-coordinate of 3 - 6 = -3.

At this point, you have enough information to make the correct answer selection. Only one answer choice has the x-coordinate of J' as -3.

__

The other coordinates are translated using similar logic. The y-coordinate of J is 2. Translating it down 1 unit subtracts 1 from the y-coordinate to make it be 2 -1 = 1. Then the coordinates of J' are (-3, 1).

We write the translation rule as ...

  (x, y) ⇒ (x -6, y -1)

This means the coordinates of each translated point have 6 subtracted from the original x-coordinate, and 1 subtracted from the original y-coordinate. The other coordinates of the figure are ...

  I(2, 4) ⇒ I'(2 -6, 4 -1) = I'(-4, 3)

  H(5, 5) ⇒ H'(5 -6, 5 -1) = H'(-1, 4)

  G(4, 1) ⇒ G'(4 -6, 1 -1) = G'(-2, 0)

3 0
3 years ago
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