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tigry1 [53]
4 years ago
10

A reaction vessel contains equal masses of iron and oxygen. How much FeO could theoretically be produced?

Chemistry
1 answer:
snow_tiger [21]4 years ago
6 0

Answer:

c

Explanation:

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mr_godi [17]
They are the same as animals ability to find food and get away from others.
8 0
4 years ago
What is the molar mass of water in the hydrate? FeSO4 • 7H2O
Rainbow [258]
M=7M(H₂O)

M=7*18.015 g/mol = 126.105 g/mol
5 0
4 years ago
Which factor most influenced the economic
Vikki [24]

It was by far "warm and wet growing seasons" that was the most important factor in terms of the South's economic development. Cotton and tobacco were the biggest exports.

Explanation:

These crops created tons of cash, had massive markets round the world, however required a stable and enormous hands to grow and harvest them.The yank South is understood for its long, hot summers, and wealthy soils in stream valleys creating it a perfect location for growing cotton. the various southern seaports and riverside docks allowed shipping cotton to remote destinations. By 1860, Southern plantations equipped seventy fifth of the world's cotton, with shipments from Houston, city, Charleston, Mobile, Savannah, and some different ports. The unquenchable European demand for cotton was a results of the commercial Revolution that created the machinery and factories to method raw cotton into vesture that was higher and cheaper than hand-made product.

6 0
4 years ago
Read 2 more answers
Using the equation MgCl2 -> Mg + Cl2, if 5.00 grams of MgCl2 is given, how many grams of Mg is produced?
motikmotik

Answer:

MgCl2-> Mg+Cl

mass 5.00g Mass=1.263g

RFM Mg=24+35.5 ×2= 95 RFM= 24

moles= 5.00÷ 95= 0.0526 Moles=0.0526

Explanation:

mas of Mg= 1.263 grams

4 0
4 years ago
Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2(g) + 3/2F2(g) -> BrF3(g) = –3
arlik [135]

Answer:

C) 712 KJ/mol

Explanation:

  • ΔH°r = Σ Eb broken - Σ Eb formed
  • 1/2Br2(g) + 3/2F2(g) → BrF3(g)

∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

∴ F2 Eb = 154 KJ/mol

⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken =  (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

∴ Eb formed: Br-F

⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

8 0
3 years ago
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