Question

A person suffering from hyponatremia has a sodium ion concentration in the blood of 0.116 M and a total blood volume of 4.7 L . Part A What mass of sodium chloride would need to be added to the blood to bring the sodium ion concentration up to 0.139 M, assuming no change in blood volume?

Answer 1

Explanation:

Normal moles of $Na^{+}$ = volume × normal concentration

                              = 4.7 × 0.139 = 0.6533 mol

Moles of $Na^{+}$ in hyponatremia blood = volume × hyponatremia concentration

                              = 4.7 × 0.116 = 0.5452 mol

Moles of NaCl to be added = moles of extra $Na^{+}$ needed

                            = 0.6533 mol - 0.5452 mol = 0.1081 mol

Mass of NaCl = moles × molar mass of NaCl

                        = 0.1081 mol × 58.443

                        = 6.317g

                        = 6.32 g (approx)

Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.