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aev [14]
3 years ago
15

A solution of hcl in water conducts electricity, but a solution of hcl in chloroform, chcl3, does not. what does this observatio

n tell you about how hcl exists in water and how it exists in chloroform?
Chemistry
2 answers:
Serhud [2]3 years ago
6 0

Explanation:

A polar covalent bond is formed due to unequal sharing of electrons between the combining atoms.

For example, HCl is a polar covalent compound.

This is because of the difference in electronegativities of both hydrogen and chlorine, partial opposite charges tend to develop on the hydrogen and chlorine atoms.

Whereas CHCl_{3} is a non-polar compound and when HCl is added to it then HCl being polar in nature is unable to dissolve.

On the other hand, water is a polar compound and when HCl is dissolved in it then it will dissociate into hydrogen and chlorine ions.

As electricity is the flow of ions or electrons. Therefore, HCl in water is able to conduct electricity because it dissociates into ions.

Therefore, we can conclude that HCl in water exists as H^{+} and Cl^{-} ions. And, HCl in CHCl_{3} exists as HCl.

PSYCHO15rus [73]3 years ago
4 0
Hydrochloric acid (HCl) dissociate on positive ions or cations of hydogen (H⁺) and negative ions or anions of chlorine (Cl⁻). When there is free cations and ions, water solution can conduct electricity. Chloroform do not dissociate on ions in water, because that is not polar molecule, so chloroform is in molecular form in solution.
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Answer:

C₂H₅O₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 0.25 g

Mass of CO₂ = 0.3664 g

Mass of H₂O = 0.15 g

Empirical formula =?

Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:

For Carbon (C):

Mass of CO₂ = 0.3664 g

Molar mass of CO₂ = 12 + (2×16) = 44 g/mol

Mass of C = 12/44 × 0.3664

Mass of C = 0.1

For Hydrogen (H):

Mass of H₂O = 0.15 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H = 2/18 × 0.15

Mass of H = 0.02 g

For Oxygen (O):

Mass of C = 0.1 g

Mass of H = 0.02 g

Mass of compound = 0.25 g

Mass of O =?

Mass of O = (Mass of compound) – (Mass of C + Mass of H)

Mass of O = 0.25 – (0.1 + 0.02)

Mass of O = 0.25 –0.12

Mass of O = 0.13 g

Finally, we shall determine the empirical formula for the compound. This can be obtained as follow:

C = 0.1

H = 0.02

O = 0.13

Divide by their molar mass

C = 0.1 / 12 = 0.0083

H = 0.02 / 1 = 0.02

O = 0.13 / 16 = 0.0081

Divide by the smallest

C = 0.0083 / 0.0081 = 1

H = 0.02 / 0.0081 = 2.47

O = 0.008 / 0.008 = 1

Multiply by 2 to express in whole number

C = 1 × 2 = 2

H = 2.47 × 2 = 5

O = 1 × 2 = 2

Thus, the empirical formula for the compound is C₂H₅O₂

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