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Alecsey [184]
3 years ago
12

A triangular section of a lawn will be converted to river rock instead of grass. Maurice insists that the only way to find a mis

sing side length is to use the Law of Cosines. Johanna exclaims that only the Law of Sines will be useful. Describe a scenario where Maurice is correct, a scenario where Johanna is correct, and a scenario where both laws are able to be used. Use complete sentences and example measurements when necessary.
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0
Your answer would be, For example, the Triangular section of a lawn is named ABC, The sides are name ABC, respectively as the opposite of the angles, with the similar letters. Like Side A is opposite angle (a). The missing side length is B, To get this, Maurice, used the Law of Cosines. In order to use this, Maurice need to have two sides, and angle between them, that is given to solve for the missing lengths, which is Sides A, and C, and an angle B. Johanna used the Law of Sines, in which, she need two angles, and an opposite sides, that should be given to find the missing Length, which is Angle B, and C, and Side C. So, Since both Laws use the remaining were given, The use of both, will result in a similar measurements.




Hope that helps!!!
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5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?​
Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0
2 years ago
Find the slope that passes through (2,-4) and (5,2)
yanalaym [24]

Hi there! :)

Step-by-step explanation:

SLOPE=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}

\frac{2-(-4)}{5-2}=\frac{6}{3}=2

<u><em>Therefore, the slope is 2.</em></u>

<u><em>Final answer is 2.</em></u>

<u><em>*The answer must have a positive sign.*</em></u>

I hope this helps you!

Have a nice day! :)

:D

-Charlie

Thank you! :)

:D

7 0
3 years ago
3(0.3x +1.3) = 2(0.4x -0.85)
Verdich [7]

Answer:

Step-by-step explanation:

3(0.3x + 1.3) = 2(0.4x - 0.85)

0.9x + 3.9 = 0.8x - 1.70

0.9x - 0.8x = - 1.70 - 3.9

0.1x = - 5.6

x = - 5.6 / 0.1

x = - 56

5 0
3 years ago
Complete the equation of the line through (-9,-9) and (-6,0)
Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis.

According to the data of the statement we have the following points:

(x_ {1}, y_ {1}): (- 9, -9)\\(x_ {2}, y_ {2}): (- 6,0)

We found the slope:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 9)} {- 6 - (- 9)} = \frac { 9} {- 6 + 9} = \frac {9} {3} = 3

Thus, the equation is of the form:

y = 3x + b

We substitute one of the points and find b:

0 = 3 (-6) + b\\0 = -18 + b\\b = 18

Finally, the equation is:

y = 3x + 18

Answer:

y = 3x + 18

7 0
3 years ago
What is the solution to the expression –2 – 3 – (–4)?
Contact [7]
-2 - 3 -(-4)= -2 - 3 + 4
-2 - 3 + 4
-5 + 4
= -1
7 0
3 years ago
Read 2 more answers
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