Her grandma will be there 40 minutes early. If you add the hours first, then it makes it 6:35. Add the 50 minutes, 7:25 is the arrival time.
Answer:
8!
Step-by-step explanation:
Answer:
The distance of flag post from Y is 38.13 m
Step-by-step explanation:
Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.
Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.
Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.
Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,



Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,



Refer attachment 1.
From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.
∠YFX+∠FYX+∠FXY=180°
∠YFX+50°+72°=180°
∠YFX=58°
Refer attachment 2.
Now the distance FY can be calculated using sin rule as follows,

Substituting the values,

Simplifying first two terms,
Cross multiplying,


m
mj thinks of a number. she adds 2 to the number then multiples the result by 3. The answer is the same as adding 5 to the number them multiplying by 2
my number is d
3 (d×2) = 2 (d+5)
3×d + 3×2 = 2×d + 2×5
3d + 6 = 2d + 10
3d +6 -6 -2d = 2d - 10 - 6
3d - 2d = 10 - 6
d = 4
Answer:
The butterfly travels 660 ft in 1.25 min.
Step-by-step explanation:
If the distance, d, a butterfly flies varies directly as the time,t in the air, then we can write the mathematical statement.

If we introduce the constant of proportionality, we obtain;

According to the question, when
,
.
We substitute these values to obtain;



The direct variation equation now becomes

When 


Therefore the butterfly will travel 660 ft in 1.25 min.