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d1i1m1o1n [39]
2 years ago
10

Can you help me on question 28!!

Mathematics
1 answer:
statuscvo [17]2 years ago
8 0
The correct answer is B, because 65+0.20x140=93. You must multiply 0.20 times 140 first, and get 28 and than add 28+65=93.
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According to the Fundamental Theorem of Algebra, which polynomial function has exactly 8 roots?
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Answer:

Therefore, the polynomial function with exactly 8 roots is f(x) = (3x^2 - 4x - 5)(2x^6 - 5).

Step-by-step explanation:

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Which ordered pair lies on the function f(x) = x^2 + 3?
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B lies on the function
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The Reds and the Cubs are playing 3 games. In each game the probability that the Reds win is 0.54. The probability of the Reds w
shusha [124]

Answer:

(a) 1.6197

(b) 1.3803

Step-by-step explanation:

(a) Let X denote the number of games the Reds win. If Reds win exactly one it means that in the other two games Reds lost i.e Cubs won. Now,  the probability of the Reds losing is determined by 1 -\text{probability of winning} = 1-0.54 = 0.46. So, if X wins exactly i times, then we should multiply the probabilities associated with

P(X=0) = \binom{3}{0} \times 0.46 \times 0.46 \times 0.46 = 0.0973

P(X=1) = \binom{3}{1} 0.54 \times 0.46 \times 0.46 = 0.3429

P(X=2) = \binom{3}{2} 0.54 \times 0.54 \times 0.46 = 0.4023

P(X=3) = \binom{3}{3} 0.54 \times 0.54 \times 0.54 = 0.1574

Now,

E(X) = \sum_{i=0}^{3} i \times P(X=i) = 1.6197

(b) Let Y denote the number of games won by Cubs. Then by the similar logic as above,

P(Y=3) = \binom{3}{0} 0.46 \times 0.46 \times 0.46 = 0.0973

P(Y=2) = \binom{3}{1} 0.54 \times 0.46 \times 0.46 = 0.3429

P(Y=1) = \binom{3}{2} 0.54 \times 0.54 \times 0.46 = 0.4023

P(Y=0) = \binom{3}{3} 0.54 \times 0.54 \times 0.54 = 0.1574

Now

E(Y) = \sum_{j=0}^{3} j \times P(Y=j) = 1.3803

8 0
3 years ago
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777dan777 [17]

Answer:

Qualitative Research

Step-by-step explanation:

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Case study is an example of qualitative research. Quantitative research depends on the mathematical formulations and relations to come to a conclusion while qualitative research does not.

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2 years ago
What is the probability of two dice being rolled and it being less than 7 and divisible by 3
Luden [163]

Answer:

Step-by-step explanation:

(1, 1) <u>(1, 2)</u> (1, 3) (1, 4) <u>(1, 5)</u> (1, 6)

<u>(2, 1)</u> (2, 2) (2, 3)<u> (2, 4)</u> (2, 5) (2, 6)

(3, 1) (3, 2) <u>(3, 3)</u><u> </u>(3, 4) (3, 5) <u>(3, 6) </u>

(4, 1) <u>(4, 2</u>) (4, 3) (4, 4)<u> (4, 5) </u>(4, 6)

<u>(5, 1)</u> (5, 2) (5, 3) <u>(5, 4)</u> (5, 5) (5, 6)

(6, 1) (6, 2) <u>(6, 3) </u>(6, 4) (6, 5) <u>(6, 6) </u>

The bold numbers are less than 7, and the <u>underlined numbers</u> are <u>divisible by 3</u>. The total number of numbers are 36.

The number of numbers that are <u>both</u> <u>underlined</u> and bold are 7.

The probability is 7/36.

8 0
3 years ago
Read 2 more answers
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