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d1i1m1o1n [39]
3 years ago
10

Can you help me on question 28!!

Mathematics
1 answer:
statuscvo [17]3 years ago
8 0
The correct answer is B, because 65+0.20x140=93. You must multiply 0.20 times 140 first, and get 28 and than add 28+65=93.
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Write the expression using rational exponents. Then simplify and convert back to radical notation.
ioda

Answer:

The radical notation is 3x\sqrt[3]{y^2z}

Step-by-step explanation:

Given

\sqrt[3]{27 x^{3} y^{2} z}

Step 1 of 1

Write the expression using rational exponents.

\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}

=a^{\frac{m}{n}}:\left({27 x^{3} y^{2} z})^{\frac{1}{3}}

$(a \cdot b)^{r}=a^{r} \cdot b^{r}:(27)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

=$(3^3)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

$=\left(3\right)\left(x}\right)} \cdot\left(y}\right)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

Simplify $3 x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3 x \sqrt[3]{y^{2} z}$

Learn more about radical notation, refer :

brainly.com/question/15678734

4 0
3 years ago
What is the value of k? <br> -k+78=98-20
Jlenok [28]

Answer:

k=0

Step-by-step explanation:

6 0
3 years ago
Katie said,"Negative numbers are integers."What was her error?
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Integer means a whole number , a number that is not fraction
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Which statement best describes Marcos equation
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The sugar company will choose from two companies to transport its sugar to market. The first company charges 5197 to rent trucks
Rudiy27
5197+175.75x=5500+150.50x
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3 0
3 years ago
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