Answer:
∠B ≅ ∠F ⇒ proved down
Step-by-step explanation:
<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>
Let us use this fact to solve the question
→ In Δs BCD and FED
∵ ∠C and ∠E are right angles
∴ Δs BCD and FED are right triangles ⇒ (1)
∵ D is the mid-point of CE
→ That means point D divides CE into 2 equal parts CD and ED
∴ CD = ED ⇒ (2) legs
∵ BD and DF are the opposite sides to the right angles
∴ BD and DF are the hypotenuses of the triangles
∵ BD ≅ FD ⇒ (3) hypotenuses
→ From (1), (2), (3), and the fact above
∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency
→ As a result of congruency
∴ BC ≅ FE
∴ ∠BDC ≅ ∠FDE
∴ ∠B ≅ ∠F ⇒ proved
The answer is the third answer choice, I and II only.
This is because both of those motions are rigid since they are just reflections and III is not a rigid motion since it is a dilation, the second triangle is bigger than the first.
Hope this helps!
Answer:
17 i think
Step-by-step explanation:
<h2>Greetings!</h2>
Answer:
One number is 
and the other number is 
Step-by-step explanation:
Let x be the smaller number and y be the bigger number.
x = x
y = 5x
6x + 3y = 3
6x + (3 * 5x) = 3
6x + 15x = 3
(÷3)
2x + 5x = 1
7x = 1
x =
6x + 3y = 3
6() + 3y = 3
+ 3y = 3
3y = 3 -
3y = 
Divide both sides by 3 to get 1y:
y =
So one number is and the other number is
<h2>Hope this helps!</h2>
6/7 × 4 would be the correct answer. This is because 6/7 × 4= 3 3/7 which is equal to 4/7 × 6= 3 3/7. No other expression would equal 4/7 × 6
