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I am Lyosha [343]
3 years ago
10

5 examples of oxidation and reduction

Chemistry
2 answers:
Masja [62]3 years ago
7 0

Answer:

combination, decomposition, displacement, combustion, and disproportionation

Likurg_2 [28]3 years ago
3 0
Combination,decomposition,displacement, disproportionation, and combustion. Hope this helped!
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Classify each of the following particulate level illustrations as a representation of either a pure substance, a homogeneous mix
Anarel [89]

Answer:

The classification and illustrations are attached in the drawing.

Explanation:

It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.

On the other hand, the homogeneous mixture is identified by noting that its atoms are more united with respect to the heterogeneous mixture, highlighting that in homogenous mixtures the atoms, elements or substances are not visible to the naked eye and are in a single phase, instead in the heterogeneous mixture if they can be differentiated.

4 0
4 years ago
Can anyone answer this? (I thank)
Mamont248 [21]
CO2 will be the first to boil because it will be the first to warm up because it is the closest temperature to 0
4 0
3 years ago
How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0 degrees Celsius to 80 degrees Celsius? (
lapo4ka [179]
The heat required to raise the temperature of a certain mass of sample to a specific temperature change, we use the formula mCpΔT where m is mass, Cp is the specific heat of the substance and ΔT is the temperature change. In this case, we substitute and form 1.25 g x 0.057 cal/g C *20 C equal to 1.425 calories.
7 0
4 years ago
How many moles are present in 25.0 grams of potassium permanganate, KMnO,? ​
poizon [28]

Answer: 0.158

Explanation:

7 0
3 years ago
Fill in the coefficients that will balance the following reaction: a0Ca + a1CO2 + a2O2 → a3CaCO3
VashaNatasha [74]
The chemical equation without coefficients is:


Ca + CO2 + O2 --------> Ca CO3


You can balance that equation by trial an error.


This is the chemical equation balanced:


2Ca + 2CO2 + O2 --------> 2Ca CO3


Count the atoms on each side to check the balance


Atom    Left side         right side

Ca         2                     2 

C           2                     2

O          2*2 + 2 = 6       2*3 = 6


Then those are the coefficients:

a0 = 2

a1 = 2

a2 = 1

a3 = 2
6 0
4 years ago
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