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docker41 [41]
3 years ago
8

Similarities about the inner and outer planets

Chemistry
2 answers:
amm18123 years ago
7 0

Answer:

they are round

Explanation:

Sonja [21]3 years ago
4 0

Explanation:

The similarities of the inner and outer planets are The inner planets are often referred to as “terrestrial” or “rocky” planets. The outer planets, meaning those planets outside the asteroid belt, are called “gas giants.” The terrestrial planets are small (astronomically speaking). Earth is the largest one, with a diameter of about 8000 miles

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When particles that attract each other are allowed to come to together, energy is ______
Rufina [12.5K]

Answer:

Released

Explanation:

When particles that attract each other come together, energy is usually released. The combination of the two particles is expected to result in a lower energy system. This lower energy system will be more stable than the different individual particles.

Hence, as this lower energy system is formed, the excess energy originally possessed by the particles is evolved hence energy is released when particles that attract each other are allowed to come together.

5 0
3 years ago
Which of these statements best describes how an increase in the amount of Sun’s heat reflected by the Earth’s surface and atmosp
Korolek [52]

If the Suns heat is being reflected, then it is making the Earth cooler.

7 0
3 years ago
Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0
3 years ago
Draw one line connecting each factor that increases the rate of a
VLD [36.1K]

Answer:

Adding a catalyst - More collisions every second and more collisions with enough energy to break bonds.

Increase in pressure - more collisions every second

Increase in temperature - more collisions every second with enough energy to break bonds

Explanation:

According to the collision theory, chemical reaction occurs as a result of collision between reacting particles. Only particles that possess energy above the activation energy of the reaction can collide and result in product formation. Collision of particles having energy less than the activation energy merely result in elastic collisions.

Adding a catalyst lowers the activation energy of the reaction. If the activation energy is lowered, more reactants collide and more of those collisions now have enough energy to break bonds.

When the temperature is increased, the particles become more energetic hence more collisions with energy to break bonds occur.

Increase in pressure brings the reactant particles into close proximity hence more collisions occur.

4 0
3 years ago
You do an experiment in which you need 0.25 mole of tyrosine (C,H11 NO3).
Marina CMI [18]

Answer:

B.90.5 g

Explanation:

not 100%sure hehe

6 0
3 years ago
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