Answer:
C. 590 mph

Explanation:
Given:
- velocity of jet,

- direction of velocity of jet, east relative to the ground
- velocity of Cessna,

- direction of velocity of Cessna, 60° north of west
Taking the x-axis alignment towards east and hence we have the velocity vector of the jet as reference.
Refer the attached schematic.
So,

&


Now the vector of relative velocity of Cessna with respect to jet:



Now the magnitude of this velocity:

is the relative velocity of Cessna with respect to the jet.
Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, 
Area of cross section, 
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
R = W
or

Where
is the density of air = 1.225 kg/m³
C is drag coefficient
So,

So, the drag coefficient is 1.01.
The President is Xi Jinping
Velocity = fλ
where f is frequency in Hz, and λ is wavelength in meters.
2.04 * 10⁸ m/s = 5.09 * 10¹⁴ Hz * λ
(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴ Hz ) = λ
4.007*10⁻⁷ m = λ
The wavelength of the yellow light = 4.007*10⁻⁷ m
Answer:
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