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hodyreva [135]
3 years ago
5

Ground-based radio telescopes can collect data from distant objects in space

Physics
2 answers:
sasho [114]3 years ago
6 0

Ground-based radio telescopes can collect data from distant objects in space  during the day or night and in MANY different weather conditions.

BUT ...

-- of course, they have to avoid pointing at the Sun, since the Sun is a loud, humongous source of radio signals !

-- of course, they have to shut down during lightning storms and most rain, because lightning is a loud, humongous source of radio signals, and rain can generate radio static noise.  Rain can also create puddles and unsymmetric wetting inside the radio "dish" antenna, which really messes up the gain and directional pattern of the antenna.    

Arada [10]3 years ago
4 0
Answer is A. Because the telescope are use in night
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List an example of each of the four classes polymers that living things make and use
slamgirl [31]


The four classes of polymers are:

1. Nucleic acids.  Examples are DNA and RNA

2. Protein. Examples are enzymes and hemoglobin

3. Carbohydrates. Examples as starch and glycogen

4. Lipids. Examples are triglycerides and phospholipids

The building blocks of nucleic acids are called bases and there are four types known as Guanine, Adenine, Thymine and Cytosine.

The building blocks of carbohydrates are glucose molecules.

The building blocks of protein are amino acids.

The building blocks of lipids are a combination of fatty acids and glycerol.

6 0
4 years ago
A force on a particle depends on position such that F(x) = (3.00 N/m2)x2 + (6.00 N/m)x for a particle constrained to move along
Pachacha [2.7K]

Answer:

The work done by a particle from x = 0 to x = 2 m is 20 J.

Explanation:

A force on a particle depends on position constrained to move along the x-axis, is given by,

F(x)=(3\ N/m^2)x^2+(6\ N/m)x

We need to find the work done on a particle that moves from x = 0.00 m to x = 2.00 m.

We know that the work done by a particle is given by the formula as follows :

W=\int\limits {F{\cdot} dx}

W=\int\limits^2_0 {(3x^2+6x){\cdot} dx} \\\\W={(x^3}+3x^2)_0^2\\\\\W={(2^3}+3(2)^2)\\\\W=20\ J

So, the work done by a particle from x = 0 to x = 2 m is 20 J. Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
In half wave rectifier circuit the diode and load resistance are connected in ...to ac power source​
Fudgin [204]
Working of a Half wave rectifier
The diode is connected in series with the secondary of the transformer and the load resistance RL. The primary of the transformer is being connected to the ac supply mains. The ac voltage across the secondary winding changes polarities after every half cycle of the input wave.
5 0
3 years ago
The critical angle for water is 49°. If a ray of light
Sonja [21]

Answer:

Snell's Law states

Ni sin i = Nr sin r

Judging from the question the source of the ray is in the water (directed up)

or NI = 1 / sin 49      Ni = 1.325 deg     the critical angle

From inside the pond:

Nr = 1.325 * sin 45 / 1 = 94 deg  

So refraction can occur  outside the pond and you do not have total internal refection.

 

3 0
3 years ago
I need help ASAP!!!! Here’s the question. Stephanie is going to buy an ice cream cone. She can pick a sugar cone or a waffle con
PolarNik [594]

Answer:

Six

Explanation:

Assuming she can only have ONE flavor in her cone

  2 cone types   *    3 flavors   =   6 combos

7 0
2 years ago
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