In the figure below, a long circular pipe with outside radius R = 2.57 cm carries a (uniformly distributed) current i = 10.4 mA
into the page. A wire runs parallel to the pipe at a distance of 3.00R from center to center. Find the magnitude of the current in the wire in milliamperes such that the ratio of the magnitude of the net magnetic field at point P to the magnitude of the net magnetic field at the center of the pipe is 4.74, but it has the opposite direction.
2 answers:
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Answer:
a) s
b) 3.41 mm
Explanation:
a)
We take the speed of light, c = m/s and the refractive index of glass as 1.517.
Speed = distance/time
Time = distance/speed
Refractive index, n = speed of light in vacuum / speed of light in medium
b)
We take the refractive index of water as 1.333.
Speed in water = speed in vacuum / refractive index of water
Distance = speed * time
d = 3.41 mm
Answer:
Explanation:
given,
frequency of tuba.f = 64 Hz
Speed of train approaching, v = 8.50 m/s
beat frequency = ?
using Doppler's effect formula
v_s is the velocity of the source
v is the speed of sound, v = 340 m/s
now,
f' = 65.64 Hz
now, beat frequency is equal to
hence, beat frequency is equal to 1.64 Hz