The perimeter of this figure is 42.5 cm. Find the area of this figure.
1 answer:
The picture in the attached figure
let
AB=x
we know that
perimeter of the figure=10*x
perimeter=42.5 cm
so
42.5=10*x
x=42.5/10
x=4.25 cm
area of the figure=area of rectangle +area of square
area of rectangle=4.25*(4.25*3)----> 54.1875 cm²
area of square=4.25²----> 18.0625 cm²
area of the figure=54.1875+18.0625-----> 72.25 cm²
the answer is
72.25 cm²
let
AB=x
we know that
perimeter of the figure=10*x
perimeter=42.5 cm
so
42.5=10*x
x=42.5/10
x=4.25 cm
area of the figure=area of rectangle +area of square
area of rectangle=4.25*(4.25*3)----> 54.1875 cm²
area of square=4.25²----> 18.0625 cm²
area of the figure=54.1875+18.0625-----> 72.25 cm²
the answer is
72.25 cm²
You might be interested in
To find the inverse
replace f(x) with y
switch all x and y
solve for y
replace y with f⁻¹(x)
f(x)=x^2-9
y=x^2-9
x=y^2-9
x+9=y^2
sqrt both sides
replace
f⁻¹(x)=
that is the inverse
replace f(x) with y
switch all x and y
solve for y
replace y with f⁻¹(x)
f(x)=x^2-9
y=x^2-9
x=y^2-9
x+9=y^2
sqrt both sides
replace
f⁻¹(x)=
that is the inverse