$\displaystyle\\|\Omega|=\binom{16}{2}=\dfrac{16!}{2!14!}=\dfrac{15\cdot16}{2}=120\\|A|=\binom{5}{2}=\dfrac{5!}{2!3!}=\dfrac{4\cdot5}{2}=10\\\\P(A)=\dfrac{10}{120}=\dfrac{1}{12}\approx0.083$

8 0

2 years ago

A line has a slope of 0.5<br> and passes through the point (0,5). What is the equation of the line?

EleoNora [17]

Step-by-step explanation:

Hi there!

From the question;

The slope of the line is 5/10 or 0.5.

Also the equation of the line passes through the point (0,5).

Note: Use one point formula. {i.e (y-y1)=m(x-x1)}

So, use the formula here and keep the values;

(y-5) = 5/10(x-0)

or, 10(y-5) = 5x

or, 10y-50 = 5x

or, 5x - 10y +50 = 0

Therefore, the required equation is 5x - 10y +50 = 0 or x-2y+10 = 0.

Hope it helps!

6 0

2 years ago