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Physics

1 answer:

Afina-wow [57]3 years ago

3 0

I believe the answer is D. much smaller because most are only a little bigger than Jupiter.

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Satellite C revolves around Earth 10 times a day. What is the radius of its orbit, measured from Earth's center? Assume that Ear

frez [133]

The radius of its orbit, measured from Earth's center, will be 1.44 × 10⁷ mm.

<h3>What is Newton's law of gravitation?</h3>

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Given data in problem is;

The mass of Earth is, $\rm m_E = 5.98 \times 10^{24} \ kg$

Gravitational constant, G =6.674 × 10⁻¹¹ N m₂/kg²

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

$\rm F_g = \frac{Gm_sm_e}{r^2}$

The centripetal force due to rotation of the satellite;

$\rm F_c = \frac{m_s v^2}{r}$

The centripetal and the gravitational force are equal;

$\rm F_g = F_c \\\\ \frac{Gm_sm_e}{r^2} = \frac{m_s v^2}{r} \\\\ r = G \frac{m_E }{v^2 } \\\\ r = G \frac{m_E }{(r \omega )^2 } \\\\ r = \sqrt[3]{\frac{Gm_E}{\omega^2}} \\\\ r = \sqrt[3]{\frac{6.67 \times 10^{-11}(5.98 \times 10^{24})}{(3.63 \times 10^{-4})^2}} \\\\ r = 1.44 \times 10^7 \ mm$