A straight wire carrying a 3.30-A current is placed in a uniform magnetic field of magnitude 0.272 T directed perpendicular to t
he wire. (a) Find the magnitude of the magnetic force on a section of the wire having a length of 12.7 cm. N (b) Explain why you can't determine the direction of the magnetic force from the information given in the problem
the bold incate vector. This equation can be used in the form of magnitude and find the direction separately with the rule of the right hand
F = i L B sin θ
Where θ is the angle between the direction (L) and the magnetic field, if the two are perpendicular sin 90 = 1
Let's calculate
F = 3.30 0.127 0.272
F = 0.114 N
b) to know the direction of the magnetized field we must know the direction of B and L, but in the problem they tell us that they are perpendicular, but not the direction of each
They are too small are never in the same place. Electrons are constantly moving in random motion within the electron cloud, making them impossible to follow.
