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Tcecarenko [31]
3 years ago
12

A straight wire carrying a 3.30-A current is placed in a uniform magnetic field of magnitude 0.272 T directed perpendicular to t

he wire. (a) Find the magnitude of the magnetic force on a section of the wire having a length of 12.7 cm. N (b) Explain why you can't determine the direction of the magnetic force from the information given in the problem
Physics
1 answer:
stira [4]3 years ago
6 0

Answer:

F = 0.114 N

Explanation:

a) The magnetic force is given by the equations

    F = q v x B = I Lx B

the bold incate vector.  This equation can be used in the form of magnitude and find the direction separately with the rule of the right hand

    F = i L B sin θ

Where θ is the angle between the direction (L) and the magnetic field, if the two are perpendicular sin 90 = 1

Let's calculate

    F = 3.30 0.127 0.272

    F = 0.114 N

b) to know the direction of the magnetized field we must know the direction of B and L, but in the problem they tell us that they are perpendicular, but not the direction of each

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Answer:

The acceleration is 8 m/s²

Explanation:

The given parameters are;

The initial velocity, u = 2 m/s

The final velocity, v = 6 m/s

The distance the acceleration took place, s = 2 m

The acceleration, a, can be found from the following kinematic equation;

v² = u² + 2·a·s

By substituting the values, we have;

6² = 2² + 2 × a × 2

6² - 2² = 2 × a × 2

32 = 4·a

a = 32/4 = 8 m/s²

The acceleration, a, of the given motion = 8 m/s².

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When a magnet is moved through a coil of wire, an electric current is generated in the coil because
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Answer:When a magnet is moved through a coil of wire, an electric current is generated in the coil because

Explanation: the magnet is pushing and pulling on the coils to make it move.

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3 years ago
A. Blue light has higher energy than red light. Write 3 - 4 sentences comparing these electromagnetic waves with respect to the
frosja888 [35]

PART A)

As we know that energy of light depends on its wavelength and frequency as following formula

E = \frac{hc}{\lambda} = h\nu

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more

also we know that

\nu = \frac{c}{\lambda}

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium

PART B)

Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy

When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.

here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current

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Answer:

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In our Solar System, the inner planets are rocky because Choose one: A. warm temperatures in the inner disk caused the inner pla
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The inner planets are rocky because The warm temperatures in the inner disk caused the inner planetesimals to be formed of mostly rocky material.

What are rocky planets?

  • Rocky planets are the planet in which constituents are mostly silicate rocks or metal. They are also regarded as a planet with a solid surface.
  • The formation of rocky planets is said to have occurred billions of years ago and its process of formation is termed accretion. Through accretion are its constituents formed as the more it goes bigger, the higher the rising temperature and pressure in its core and the elements which have to undergo accreted heat up, melt, and spread. Through this process, heavier elements go deeper into the core of the planet and lighter elements float toward the surface.
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Hence, from the above, we can say that,

The warm temperatures in the inner disk caused the inner planetesimals to be formed of mostly rocky material.

Here,

Option A is correct.

Learn more about rocky planets here:

<u>brainly.com/question/22392798</u>

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