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lutik1710 [3]
3 years ago
15

-x+4=x+6 i have to solve for x

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0

Answer:

Collect like terms

-x-x=6-4

Solve

-2x=2, -x=1 or x=-1

Step-by-step explanation:

I hope this helps, please give me brainliest

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Will mark brainliest. Step-by-step please. Thank you very much.
Naily [24]

Answer:

133°

Step-by-step explanation:

angles on a straight line = 180°

180 - 144 = 36°

angles in a triangle = 180°

36 + 31 = 67

180 - 67 = 113

answer = 113°

3 0
3 years ago
10.5 in the form a/b
Lorico [155]
10.5 in the form of a/b = 105/10 = 21/2
4 0
3 years ago
Select the correct answer.
valentinak56 [21]

A

see attached for explanation

I hope it helps

7 0
3 years ago
What is the mean of the data set?
svetoff [14.1K]
B) 12.75
Just add them all together
10+15+14+8+18+11+12+12+10+10+17+16=153
The devide the anser by the ammount of numbers you added together
153÷12=12.75
8 0
3 years ago
Read 2 more answers
It is hard to calculate the volume of a mountain but several estimates put the volume of Mount Everest at around 2,413 cubic kil
scoray [572]

Answer:

About 609,000 Cowboy stadiums could fit inside of Mount Everest

Step-by-step explanation:

we have

The estimate volume of Mount Everest is at around 2,413\ km^{3}

The Dallas Cowboys Stadium has a volume of 140,000,000\ ft^{3}

step 1

Convert ft³ to km³

we know that

1 km=3,280.84 ft

so

140,000,000\ ft^{3}=140,000,000*(1/3,280.84)^{3}=0.003964\ km^{3}

step 2

To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

2,413/0.003964=608,729

Round to the nearest Thousands

608,729=609,000

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium

8 0
3 years ago
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