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2 years ago

Triangle PQR is dilated by a scale factor of 1/3 to form triangle P'Q'R'. Side RP

Mathematics

1 answer:

Bas_tet [7]2 years ago

6 0

Answer:

Step-by-step explanation:

A third of 3=1

3/3=1

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Please help.A teacher asked her pupils what their favourite school subject was.

julia-pushkina [17]

Yes this is simple just what is the angle of the whole circle and just subtract from that number.

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2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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2 years ago

PLS HELP!! will give brainliest

lubasha [3.4K]

Answer:

B. {-2, 0, 1, 3}

Step-by-step explanation:

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1 year ago

What's the value of x in the equation: 10x-6=5x34

Snowcat [4.5K]

Answer:

Step-by-step explanation:

10x-6=5x+34

-5x -5x

5x-6=34

+6 +6

5x=40

---- ----

5 5

x= 8

// have a great day //

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3 years ago

Solve the equation for x. X +9= -11

Vera_Pavlovna [14]

Answer:

x=-20

Step-by-step explanation:

x+9=-11

Subtract 9 from both sides. (-11-9=-20)

x=-20

7 0

3 years ago

Read 2 more answers