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3 years ago

5 divided by 7/8 as a fraction Pls help 44 points

Mathematics

1 answer:

topjm [15]3 years ago

5 0

Answer:

5.714 (rounded to the nearest thousandth)

Step-by-step explanation:

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Find the solution to the equation 3x+1=6x+1

LenKa [72]

The answer is x=0 :)

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3 years ago

What elements in domain has the image 5 under function f(x)= 3x+ 2?

bekas [8.4K]

Answer:

Step-by-step explanation:

hello

calculate x : 3x+2 =5

means : 3x+2-2 =5-2

3x = 3

so : x = 3/3 =1

1 is the element in domain has the image 5 under function f(x)= 3x+ 2

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2 years ago

Please help!! 10 points

hichkok12 [17]

Answer:

We conclude that:

$\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}$

Hence, option B is correct.

Step-by-step explanation:

Given the expression

$\sqrt[3]{200k^{15}}$

Apply radical rule:

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

so the expression becomes

$\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}$

first solving

$\sqrt[3]{k^{15}}$

Apply radical rule: $\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\sqrt[3]{k^{15}}=k^{\frac{15}{3}}=k^5$

then solving

$\sqrt[3]{200}$

prime factorization: 200: 2³ · 5²

$=\sqrt[3]{2^3\cdot \:5^2}$

Apply radical rule:

$\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt[3]{2^3}\sqrt[3]{5^2}$

Apply radical rule:

$\sqrt[n]{a^n}=a,\:\quad \:a\ge 0$

$=2\sqrt[3]{5^2}$

Thus, the main expression becomes

$\sqrt[3]{200k^{15}}=\sqrt[3]{200}\sqrt[3]{k^{15}}$

$=2k^5\sqrt[3]{25}$

Therefore, we conclude that:

$\:\sqrt[3]{200k^{15}}=2k^5\sqrt[3]{25}$

Hence, option B is correct.

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3 years ago

On a beach, there is a positive correlation between the number of bottles of water a person drank and the number of whales they

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I believe the best answer to that question is B

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4 years ago

Read 2 more answers

The area of a rectangle is expressed as (12m+18) square feet. If the width of the rectangle is 6 feet, choose an expression to r

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the answer is C.

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3 years ago